Kerumunan tatapan kosong


36

Masalah

Diberikan tidak ada input, tuliskan program atau fungsi yang menghasilkan atau mengembalikan string berikut:

(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)

Aturan

  • Kemenangan program terpendek.
  • Trailing whitespace diizinkan.
  • Membuntuti baris baru diizinkan.
  • Parameter yang tidak digunakan untuk fungsi diperbolehkan.

5
Catatan: string ini adalah gabungan dari substring dari (<>.<>):"(<" + "(<>" + "(<>." + ... + "(<>.<>)" + "<>.<>)" + ">.<>)" + ... + ">)"
JungHwan Min

2
Ini akan menjadi sedikit kurang "hardcode semua teks!" jika itu kerumunan yang lebih besar ...
manusia

@totallyhuman Akan memikirkannya lain kali
LiefdeWen

Jawaban:


13

SOGL V0.12 , 12 byte

pΙ2○3V?hG]‘Γ

Penjelasan:

pΙ2○3V?hG]‘   Push compressed string of the first half of the string (this is the kind of thing this compressor was made for)
           Γ  mirror, swap chars & palindromize with one character overlap

Coba Di Sini!


Senang melihat Anda memiliki juru bahasa online yang tersedia sekarang :)
Emigna

Bagaimana kamu melakukan ini? Kerja bagus !!
abhiagNitk

18

05AB1E , 16 byte

"(<>.".∞ηJÀ24£.∞

Cobalah online!

Penjelasan

"(<>."             # push this string
                   # STACK: "(<>."
      .∞           # intersected mirror
                   # STACK: "(<>.<>)"
        η          # compute prefixes
         J         # join to string
                   # STACK: "((<(<>(<>.(<>.<(<>.<>(<>.<>)"
          À        # rotate left
           24£     # take the first 24 chars
                   # STACK: "(<(<>(<>.(<>.<(<>.<>(<>."
              .∞   # intersected mirror
                   # STACK: "(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"


15

JS (Jsfuck), 10.614 byte

Tidak memiliki akses ke situs web, harus mencari tahu ini secara manual -.-

(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[+!+[]+!+[]]+(![]+[])[+!+[]+!+[]]])[+!+[]+(+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+[])]
+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+[]]
+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[+!+[]+!+[]]+(![]+[])[+!+[]+!+[]]])[+!+[]+(+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+[])]
+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+[]]
+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+!+[]+!+[]]
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+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+[]]
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+(+(+!+[]+[+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+[!+[]+!+[]]+[+[]])+[])[+!+[]]
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+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[+!+[]+!+[]]+(![]+[])[+!+[]+!+[]]])[+!+[]+(+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+[])]
+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+[]]
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+(+(+!+[]+[+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+[!+[]+!+[]]+[+[]])+[])[+!+[]]
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+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+[]]
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+(+(+!+[]+[+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+[!+[]+!+[]]+[+[]])+[])[+!+[]]
+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+[]]
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+(+(+!+[]+[+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+[!+[]+!+[]]+[+[]])+[])[+!+[]]
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+(+(+!+[]+[+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+[!+[]+!+[]]+[+[]])+[])[+!+[]]
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+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+[]]
+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+!+[]+!+[]]
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+(+[]+[])[([![]]+[][[]])[+!+[]+[+[]]]+(!![]+[])[+[]]+(![]+[])[+!+[]]+(![]+[])[+!+[]+!+[]]+([![]]+[][[]])[+!+[]+[+[]]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(![]+[])[!+[]+!+[]+!+[]]]()[+!+[]+!+[]]
+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[+!+[]+!+[]]+(![]+[])[+!+[]+!+[]]])[+!+[]+(+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+[])]

Penjelasan:

Sebagian besar karakter relatif mudah: Untuk kurung dieksekusi

   ([]["fill"]+[])[13] // '('

   ([]["fill"]+[])[14] // ')'

Perhentian penuh didapat dengan membuat js membuat angka notasi ilmiah seperti 1.1e + 21 Dan mengambil karakter titik setelah dikonversi ke string

Kurung kotak lebih sulit, kita harus menjalankan fungsi untuk membuat string objek html miring dan mencuri kurung sudut. Trik utama dalam ini adalah mendapatkan 'c' untuk kata miring, yang membutuhkan membangun fungsi lain untuk mengambil c dari 'fungsi'

Ada banyak ruang untuk perbaikan di sini, sebagian besar di mana fungsi digunakan untuk mendapatkan tanda kurung. Saya juga ingat cara yang lebih mudah untuk mendapatkan karakter 'c' jika huruf miring lebih baik, tetapi saya harus melihat file lama saya untuk menemukannya

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3
Ini terlihat terlalu lama bahkan untuk JSFuck tetapi +1 untuk upaya lembar melakukan ini secara manual.
F1Krazy

Saya memanggil BS untuk melakukannya secara manual. Anda harus melakukan sesuatu untuk mengotomatisasi pembuatan itu.
Patrick Roberts

10660 byte sebenarnya.
CalculatorFeline

6
@PatrickRoberts Aku yakin dia pikir itu secara manual dan menggunakan kekuatan ctrlc dan v
bleh

1
@ PatrickRoberts Ini bukan program yang sangat sulit, ini hanya kasus memahami bagaimana membangun setiap karakter. Sebagai contoh dasar, cara untuk mendapatkan karakter 't' adalah dengan membuat array kosong '[]', dilemparkan ke angka untuk membuat angka 0: '+ []' dan kemudian menerapkan operator tidak ke sana untuk melemparkan ke boolean true '! + []'. Kemudian dilemparkan ke string, dengan menambahkan array kosong lagi dan memasukkannya ke dalam tanda kurung untuk memberi kita string "benar" '(! + [] + [])' Dan akhirnya mengambil huruf nol dengan '(! + [] + []) [+ []] '
Rugnir

12

C # (Mono) , 54 52 byte

s=>"(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"

Cobalah online!

-2 byte terima kasih kepada Kevin Cruijssen

RIP C #


Saya tahu perasaan (Jawa). Tapi, Anda bisa menghemat dua byte. Jejak ;tidak dihitung untuk jawaban lambda. Dan ()dapat diganti dengan satu karakter ( nullobjek yang tidak digunakan ). Meta postingan yang relevan untuk yang kedua.
Kevin Cruijssen

1
@KevinCruijssen Ya saya tentukan parameter fungsi yang tidak digunakan diizinkan begitu s=>baik-baik saja.
LiefdeWen

-1: Tidak ada upaya yang dilakukan untuk golf jawaban dengan cara apa pun.
MechMK1

@ MechMK1 itu intinya, itu benar-benar golf mungkin di C #. Output literal string adalah cara tersest untuk menampilkan string khusus ini dalam bahasa tertentu ini. Lihat jawaban C #
Erlantz

@ Skidsdev saya masih menganggap itu bertentangan dengan semangat Code Golf, membosankan untuk menulis dan membosankan untuk dibaca. Maksudku, pilihanku tidak dihitung karena aku tidak berpartisipasi aktif, jadi jangan khawatir tentang itu. Hanya 2 sen saya, bisa dikatakan.
MechMK1


7

V , 28 27 25 22 byte

3? 4? bytes terima kasih kepada @KritixiLithos

i(<>.<>)òÙxlHÄ$xGòxÍî

Cobalah online!

i(<>.<>)                'insert (<>.<>)
         ò        ò      'recursively
          Ù              'duplicate this (bottom line) down
           x             'delete the first character
            l            'and break when there's only one character left
             H           'go to the top of the buffer
              Ä          'duplicate that line up
               $x        'delete the last character
                 G       'and go back to the bottom of the buffer
                   x     'delete the extra ) left by the loop
                    Íî   'and remove all newlines


Anda bisa menggantinya hxdengan adil X.
Kritixi Lithos

Dan dkHxògJ1 byte lebih pendek dari dkVHgJ0x.
Kritixi Lithos

Ya, Íîhal DJ juga bekerja
nmjcman101

Saya mendapatkan i(<>.<>)òÙxlHÄ$xGòddÍî23
Kritixi Lithos

@KritixiLithos Aku benar-benar HANYA beralih lXuntuk xljuga: D
nmjcman101

7

R , 42 byte

cat(substring('(<>.<>)',-4:6,2:12),sep='')

Program yang cukup sederhana yang memanfaatkan cara substring bekerja di R. Jadi substring('(<>.<>)',-4:6,2:12)menghasilkan vektor berikut

> substring('(<>.<>)',-4:6,2:12)
 [1] "(<"      "(<>"     "(<>."    "(<>.<"   "(<>.<>"  "(<>.<>)" "<>.<>)"  ">.<>)"  
 [9] ".<>)"    "<>)"     ">)"  

cat dengan pemisah kosong output ke STDOUT dalam format yang diperlukan.

Cobalah online!



5

TrumpScript, 70 Bytes

Saya tahu, ini solusi yang membosankan.

say "(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"
America is great

Tetap dilakukan dengan baik.
Adam

4

Brachylog , 14 byte

"(<>.<>)"aᶠckb

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"(<>.<>)"           #   string
         aᶠ         #       get all Affixes (pre- and suffixes)
           c        #       Concatenate
            kb      #       remove last (Knife) and first (Behead)

Sampai sekarang wajah penuh tampaknya digandakan, tetapi Anda dapat memperbaikinya dengan hanya mengubah menjadi .
String Tidak Terkait

3

C (gcc) , 59 57 byte

2 4 byte kurang dari puts()solusi sederhana . Pasti ada beberapa solusi rekursif yang elegan, tetapi sejauh ini overhead menjadi terlalu besar pada setiap upaya.

f(i){for(i=1;i++<12;)printf("%.*s",i,"(<>.<>)"+i/7*i%7);}

Cobalah online!


3

Brainfuck, 198 175 167 Bytes

Saya belum pernah melakukan codegolf, jadi ini yang pertama. Umpan balik sangat dihargai.

++++[>+++++<-]>[>++>+++>+++>++>++[<]>-]>.>.<.>.>++.<<.>.>.>>++++++.<<<<.>.>.>>.<<<.<.>.>.>>.<<<.>.<<.>.>.>>.<<<.>.>+.<<.>.>>.<<<.>.>.<.>>.<<<.>.>.>.<<<.>.>.<<.>.>.<.>.

Cobalah online!

Saya mencari solusi yang paling jelas menurut saya. Pertama, saya mengatur sel 1-5 ke salah satu huruf "(). <>". Lalu saya pergi ke sel yang tepat dan menampilkan karakter.

UPDATE: Saya mengubah urutan karakter muncul pada "tape" membuat program lebih pendek dan lebih efisien.

UPDATE 2: Baru saja meninjau kembali posting saya setelah beberapa saat dan menyadari, bahwa dengan menggunakan urutan yang lebih pendek untuk mengatur sel saya dapat menyimpan beberapa byte.


Selamat datang di PPCG! :)
Shaggy

Bagus, jawaban pertama, biasanya jawaban yang tidak segera jelas bagaimana mereka bekerja perlu penjelasan tetapi tantangan ini cukup sepele sehingga tidak terlalu dibutuhkan. Tetapi jika Anda melakukan brainfuck 1.200 byte di masa depan hanya penjelasan sederhana berjalan jauh.
LiefdeWen

Saya pasti akan melakukan itu di masa depan.
Debu

Oke, saya menambahkan deskripsi kode saya yang pendek (dan agak buruk).
Debu

2

JavaScript, 47 byte

g=(i=2)=>i>12?'':'(<>.<>)'.slice(i-14,i)+g(i+1)
f=(i=11)=>i?f(i-1)+'(<>.<>)'.slice(i-13,i+1):''

// Both of the above work and are the same size

document.write('<pre>Actual g(): ' + g() + '\nActual f(): ' + f() + '\nExpected:   (<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)</pre>');

Menggunakan metode yang sama dengan jawaban Rod's Python .



2

Arang , 20 byte

A(<>ι(<ιι.ι.<ι.ιι.‖B

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Terima kasih kepada Destructible Lemon untuk memperhatikan pola (-4).

AST:

Program
├A: Assign
│├'(<>': String '(<>'
│└ι: Identifier ι
├Print
│└'(<': String '(<'
├Print
│└ι: Identifier ι
├Print
│└ι: Identifier ι
├Print
│└'.': String '.'
├Print
│└ι: Identifier ι
├Print
│└'.<': String '.<'
├Print
│└ι: Identifier ι
├Print
│└'.': String '.'
├Print
│└ι: Identifier ι
├Print
│└ι: Identifier ι
├Print
│└'.': String '.'
└‖B: Reflect butterfly
 └Multidirectional

Apa yang ‖Bdilakukan pada dasarnya adalah palindromize secara visual.


Mohon penjelasannya.
CalculatorFeline

@CalculatorFeline Menambahkan AST sebagai dikembalikan oleh -a.
Erik the Outgolfer

Hah. Itu lebih berguna daripada yang saya pikir.
CalculatorFeline

Saya pikir ini akan menjadi lebih jelas bahkan jika Anda baru saja menambahkan bahwa cetak tersirat dengan objek
Destructible Lemon

@DestructibleLemon Tapi AST sudah memiliki Prints di sana, tidak yakin apa yang Anda maksud.
Erik the Outgolfer

2

C (gcc) , 61 byte

Saya tahu ini lumpuh tetapi jauh lebih pendek daripada solusi saya yang lain ...

f(){puts("(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)");}

C (gcc) , 103 byte

Ini adalah versi di mana saya mencoba menjadi agak rumit ...

char*e="(<>.<>)<>.<>)>.<>).<>)<>)>)";f(i,n){for(n=2;n<8;n++)for(i=0;i<n;i++)putchar(e[i]);puts(&e[i]);}

C (gcc) , 117 115 byte

Versi rekursif yang sepenuhnya rumit ...

char*e="(<>.<>)";main(i,j){if(i<6){for(++i,j=0;j<i;putchar(e[j++]));main(i);}else if(i<12)printf(e+i++-6),main(i);}

Cobalah online!


1
Tolong juga bagikan solusi tanpa-kode Anda. Meskipun lebih lama saya yakin itu jauh lebih menarik daripada yang sepele ini.
Laikoni

2

Sekelompok tatapan kosong menonton Batman untuk menghormati Adam West ...

C # (.NET Core) , 393 byte

s=>{string b="NanananaNanaBATMAN!NanaBATMAN!NANANanaBATMAN!NANAnanaNanaBATMAN!NANABATMAN!NanaBATMAN!NANABATMAN!naNABATMAN!NANABATMAN!naNANAnaNANABATMAN!naNANANABATMAN!naNABATMAN!naNANAnanaNA",r="",t;for(int i=0;i<176;)if(b[i]=='B'){r+="<>";i+=7;}else{t=b.Substring(i,4);if(t=="Nana")r+="(";else if(t=="nana")r+="<";else if(t=="NAna")r+=">";else if(t=="NANA")r+=".";else r+=")";i+=4;}return r;}

Cobalah online!


2

q , 29 byte

raze"(<>.<>)"{(y-5)_x}/:(!)11

-2 byte terima kasih kepada streetster

EDIT untuk penjelasan:

Bahasa diinterpretasikan dari kanan ke kiri.

Bagaimana itu bekerja

raze"(<>.<>)"{(y-5)_x}/:(!)11
                        (!)11 /yields indices [0-10], right parameter of function (y)
                      /:      /each right: loop right parameter of a dyadic function
             {       }        /function
    "(<>.<>)"                 /left parameter of function (x)
              (y-5)           /subtract 5 from y (indices)
                   _          /remove first y chars from x, or last y chars if negative
raze                          /flatten string output to produce the final string

4
Penjelasan di sini akan bagus.
Gryphon - Reinstate Monica

1
Anda dapat menghapus spasi sebelum _xuntuk 1 byte, dan mengubah til 11ke (!)11untuk penghematan 1 byte lain = 2 byte disimpan :)
streetster

@streetster hal-hal hebat :)
B.Wong

2

Haskell , 55 45 byte

map take[2..7]++map drop[1..5]>>=($"(<>.<>)")

Cobalah online!

Jawaban Haskell pertama untuk mengalahkan solusi hardcoded!

Penjelasan

Cara jawaban ini bekerja adalah dengan membuat daftar fungsi yang akan diterapkan ke string (<>.<>). Pertama kita membangun bagian kiri dan tengah

map take[2..7]

yang memberi kita semua awalan dari ukuran dua hingga tujuh. Kemudian kita membangun dengan benar

map drop[1..5]

yang memberi kita semua sufiks dari ukuran enam hingga dua.

Setelah kami memiliki daftar fungsi, kami menggunakan bind monadic ( >>=) yang hanya concatMaplebih pendek. Fungsi yang kami concatmap dengan adalah ($"(<>.<>)")yang menerapkan input ke string (<>.<>).

Ini membuat string.



1

Java 8, 52 byte

x->"(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)>)"

Membosankan, tetapi tidak ada cara untuk membuat ini lebih pendek di Jawa .. Hanya menginisialisasi temp String sudah 11 byte .. ( String t="something";), dan menggunakan substringbeberapa kali tentu biaya terlalu banyak byte ..

Alternatif terpendek untuk pengembalian literal mungkin adalah ini (58 byte):

x->"(<(x(x.(x.<(x.x(x.x)x.x)>.x).x)x)>)".replace("x","<>")

Coba di sini.


Juga berfungsi dalam JavaScript, menggunakan fungsi "panah gemuk" ( =>) jika Anda ingin menambahkannya.
Shaggy

@Shaggy Nah, Anda dapat menyimpan jawaban JavaScript jika mau. Hal yang sama berlaku untuk C # yang juga sudah memiliki jawaban terpisah.
Kevin Cruijssen

1

Python 2, 57 byte

print''.join("(<>.<>)"[max(0,n-5):n+2]for n in range(11))

Saya mengatakan itu terlihat seperti sekelompok burung hantu mengintip di belakang pemimpin mereka. Hanya mengatakan.



1

brainfuck , 245 210 byte

Golf sedang berlangsung.

>++++++++[<+++++>-]>++++++[<++++++++++>-]>++++++[<++++++++++>-]<++>>++++++++[<+++++>-]<++++++<<<.>.<.>.>.<<.>.>.>.<<<.>.>.>.<<.<.>.>.>.<<.>.<<.>.>.>.<<.>.<<+.>.>.>.<<.>.<<.>>.>.<<.>.<<.>>>.<<.>.<<.>.>.<<.>>.<<.

Cobalah online!


1

Haskell, 95 byte

import Data.List
import Control.Arrow
concat$tail$init$uncurry(++)$inits&&&tail.tails$"(<>.<>)"

Ini jauh lebih lama dari 49 byte yang diperlukan untuk string literal dengan output, tetapi yang terbaik yang bisa saya lakukan untuk memanfaatkan struktur . Seperti biasa, saya suka panah, dan inits &&& tailsmemang menghasilkan tuple dari daftar substring terkemuka dan daftar substring trailing input. Kemudian kedua elemen tuple tersebut disatukan dalam satu daftar dengan meneruskan tuple ke ++, dan daftar tersebut concatditetapkan ke satu string besar. The taildan initpanggilan menghindari duplikasi (<>.<>)di tengah (satu yang dihasilkan oleh inits, yang lain oleh tails) dan drop kurung yang tidak diinginkan dari awal dan akhir, mengambil hanya substring panjang 2 atau lebih ke rekening.


Bisakah Anda menambahkan penjelasan?
CalculatorFeline

@CalculatorFeline Done
Bergi

1

Jelly , 18 byte

“(<>.<>)”ḣJœ|ṫJ$ḊṖ

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Bagaimana itu bekerja

“(<>.<>)”ḣJœ|ṫJ$ḊṖ  Main link. No arguments.

“(<>.<>)”           Set the argument and return value to s := "(<>.<>)".
          J         Yield all indices of s, i.e., [1, 2, 3, 4, 5, 6, 7].
         ḣ          Dyadic head; yield s's prefixes of lengths 1 to 7.
               $    Combine the two links to the left into a chain.
              J         Indices; yield [1, 2, 3, 4, 5, 6, 7].
             ṫ          Dyadic tail; yield s's postfixes of lengths 1 to 7.
           œ|       Multiset union; concatenate the results to both sides,
                    discarding the copy of s. (s is both a prefix and a postfix.)
                Ḋ   Dequeue; remove the first prefix, i.e., "(".
                 Ṗ  Pop; remove the last postfix, i.e., ")".

1

C (dentang) , 62 61 byte

main(n){while(write(++n<13,n/7*(n-7)+"(<>.<>)",n/7?14-n:n));}

Ini berakhir hanya setelah batas waktu pada TIO karena penulisan ke input standar gagal, tetapi akan berakhir di terminal. Program ini bergantung pada urutan evaluasi tertentu (perilaku tidak terdefinisi) dan tidak akan bekerja dengan, misalnya, gcc.

Terima kasih kepada @Steadybox untuk ide yang menghemat satu byte!

Cobalah online!

Verifikasi

$ cat crowd.c
main(n){while(write(++n<12,n/7*(n-7)+"(<>.<>)",n/7?14-n:n));}
$ clang -o crowd crowd.c 2> /dev/null

$ ./crowd 0> /dev/null
(<(<>(<>.(<>.<(<>.<>(<>.<>)<>.<>)>.<>).<>)<>)

Versi alternatif, 62 byte

main(n){while(++n<13)write(1,n/7*(n-7)+"(<>.<>)",n/7?14-n:n);}

Dengan biaya satu byte lagi, solusinya menjadi lebih portabel.

Cobalah online!


1
60 byte sebagai fungsi , tetapi mungkin tidak dapat diandalkan.
Steadybox


@ Dennis Ya, (<ada yang hilang di sana.
Erik the Outgolfer


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