Kotak dan kotak [ditutup]

8

Kotak terlihat simetris, dan begitu juga kode yang diperlukan.

Tujuan : Menulis program yang kode sumbernya adalah bujur sangkar solid (N baris dengan huruf N yang dapat dicetak, karakter spasi putih setiap baris) dan mencetak kuadrat dengan ukuran yang sama. Suatu program (atau keluaran) dengan lebar dan tinggi yang tidak konsisten tidak valid. (mis. 6x5)

Contoh (HQ9 +)

QAA
AAA
AAA

Persyaratan

  • Sumber dan output harus mengandung N baris, dan N karakter yang dapat dicetak setiap baris, diikuti oleh 1 linefeed. Program Anda tidak boleh mengandung atau menampilkan karakter kontrol apa pun (kecuali LF atau CR-LF) atau spasi putih (Spasi, Tab, VTab)
  • Celah standar membosankan, jangan gunakan itu.
  • Suatu program (dan keluaran) dengan hanya satu karakter pada dasarnya tidak ada. N setidaknya harus dua.
  • Konten output tidak masalah, asalkan sesuai dengan aturan 1
  • Aturan khusus : Do tidak menggunakan komentar atau kode yang tidak tidak mempengaruhi output untuk "mengisi" kode Anda.
    Untuk lebih jelasnya, Anda diizinkan untuk menggunakan i++;i++;... i++;alih-alih i+=10;, tetapi Anda tidak harus mendefinisikan variabel string s="placeholder"tetapi tidak pernah menggunakannya nanti. Sangat mudah untuk mengatasi aturan ini jadi jangan terlalu ketat.
  • Jika Anda ingin menampilkan baris baru sebelum yang lainnya, tidak apa-apa tapi nyatakan bahwa Anda menggunakan aturan ini.
    Jika Anda ingin menampilkan baris terakhir tanpa umpan baris berikutnya, tidak masalah, dan Anda tidak perlu mendeklarasikannya. Namun itu tidak mempengaruhi penilaian.

Tambahan : Tolong beri nomor N (lebar / tinggi) yang digunakan oleh program Anda. Berikan deskripsi kode Anda jika memungkinkan.

Tidak perlu memberikan panjang (dalam byte) dari program Anda karena N mengatakan semuanya.

Karena ini adalah bowling kode , program dengan N terbesar dan kompleksitas tertinggi akan menang.

source-layout  printable-ascii  code-bowling 
— iBug
sumber
6
Apa jenis tantangan ini (misalnya golf kode, kontes popularitas)?
— Jakob
4
Saya tidak berpikir ini sesuai dengan standar popularitas kami. Cukup menampar tag pada pertanyaan tidak cukup. Silakan baca wiki tag untuk panduan yang lebih detail.
— Ad Hoc Garf Hunter
3
Anda juga harus mendefinisikan apa yang dimaksud dengan komentar. Ini bukan istilah yang didefinisikan sendiri.
— Ad Hoc Garf Hunter
4
Kami pernah menghadapi tantangan serupa sebelumnya. Saya sarankan membuat kode-golf ini, mungkin menambahkan sumber terbatas atau tag quine, dan mungkin menjatuhkan persyaratan no comment karena agak tidak jelas. Tidak akan melihat alasan untuk tidak membuka kembali.
— m-chrzan
5
@ iBug ini memiliki tag kode-golf selama 7 jam yang baik sebelum diubah ke sebaliknya - kode-mangkuk. Sebagian besar jawaban berusaha menemukan kuadrat minimal yang menghasilkan kuadrat. Juga, dengan batasan yang diberikan, sangat mudah untuk membuat kuadrat besar sembarang dalam kebanyakan bahasa. Menambahkan batasan akan sekali lagi tidak adil untuk jawaban saat ini.
— m-chrzan

Jawaban:

21

JavaScript (ES6), N = 5

Dengan baris baru terkemuka, bukan baris baru.

alert
((a=`
`+!!0
)+a+a
+a+a)
Luaskan cuplikan

JavaScript (ES6), N = 6

alert(
(1e5+`
`)['r'
+'epe\
'+'at\
'](6))
Luaskan cuplikan

JavaScript, N = 7

this['\
consol\
e'].log
('1234\
567\n'[
'repea\
t'](7))
Luaskan cuplikan

JavaScript, N = 202

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+[])[+!+[]]+([][[]]+[])[+[]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[][(![]
+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]]](!+[]+!+[]+!+[]+[+!+[]])[+!+[]]+(!!
[]+[])[!+[]+!+[]+!+[]]+(![]+[])[+!+[]]+(!![]+[])[+[]]+(![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]]+[
!+[]+!+[]]+[+[]]+[+[]]+(+(+!+[]+(!+[]+[])[!+[]+!+[]+!+[]]+[+!+[]]+[+[]]+[+[]])+[])[!+[]+!+[]]+[!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[
!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]])()
Luaskan cuplikan

— Darrylyeo
sumber
Ini untuk N = 4(Saya hanya tidak yakin apakah baris baru di awal diperbolehkan).
Saya punya solusi untuk N = 5 pastebin.com/9NFjBbxT
— kamoroso94
Inilah solusi untuk N = 4 tanpa baris baru terkemuka di output pastebin.com/pGvBQ1VK
— kamoroso94
Solusi N = 6 itu tidak valid karena hanya ada 5 baris.
— iBug
Saya percaya apa yang saya katakan adalah persegi , bukan persegi panjang .
— iBug
8

Perl 5, 5 × 5

print
q.u.x
$],$/
for(t
..x);

Ini sangat sedikit dikaburkan untuk membuatnya lebih menarik, jadi inilah beberapa penjelasannya: q.u. sama saja dengan'u' . Berikut xini adalah operator pengulangan , sehingga 'u'diulang $]kali. $]adalah antara 5 dan 6 , jadi 'u'diulang 5 kali. Anda kemudian menambahkan baris baru$/ dan printsemuanya. Ini semua dilakukan satu kali untuk masing-masing anggota daftar t..x: tdan xsebagai kata kunci diberi nilai 't'dan 'x'masing - masing, dan daftar demikian't','u','v','w','x' . Jadi outputnya adalah:

uuuuu
uuuuu
uuuuu
uuuuu
uuuuu
— msh210
sumber
1
Penjelasan lengkap Anda pantas mendapat upvote.
— iBug
8

Ruby, 3x3

!p\
p,\
p,p

Cetakan

nil
nil
nil

Cobalah online!

Bagaimana itu bekerja

padalah metode yang mencetak setiap argumennya, lalu mengembalikan nilai (atau larik nilai-nilai) yang dicetaknya. Jika itu disebut tanpa argumen, itu tidak mencetak apa pun dan kembali nil. Jadi, ps pada baris 2 dan 3 semuanya dievaluasi nil, dan yang pertama pmencetaknya nil.

— m-chrzan
sumber
7

Arang , n = 2

Solusi membosankan (Arang hanya mencetak ASCII secara harfiah):

sq
re

Cobalah online!

— Khusus ASCII
sumber
1
Apakah ini berarti Anda dapat membuat program tersebut sembarangan, karena hanya akan mencetaknya sendiri?
— Brian J
Ya (teks pengisi acak untuk membuat komentar ini lebih dari 15 karakter)
— ASCII-satunya
1
Hal yang sama dapat dikatakan untuk php jika file tidak dimulai dengan <?/ <?php.
— Alok
7

C, N = 7

i;main(
){for(i
=01;i<=
56;i++)
putchar
(i%8?37
:012);}

Mencetak kisi 7x7 %, yaitu

%%%%%%%
%%%%%%%
%%%%%%%
%%%%%%%
%%%%%%%
%%%%%%%
%%%%%%%
— iBug
sumber
5

brainfuck , 9x9

++[->+++<
]>+++[->+
>+<<]<--[
>+<++++++
]><<++[->
+++++<]>>
>>[<[-<.>
]<<.>>+++
++++++>-]

Cobalah online!

Output kuadrat dari +(fungsi paling mendasar dari brainfuck).

Saya akan kembali ketika saya mencari cara untuk mengubahnya menjadi quine, jadi kurang lebih 3 minggu ...

— Graviton
sumber
Masih belum menemukan cara quine ini.
— Graviton
Tidak ada yang berubah
— Graviton
4

Haskell, 7x7 6x6

f=b>>y
y=b++n
n="\n"
b=c++d
c=d++d
d="--"

Keluaran

------
------
------
------
------
------

Cobalah online!

Bagaimana itu bekerja:

f=             -- main function which returns the string
  b>>y         --   length b copies of y, i.e. 6 times y, because: 

d="--"         -- basic building block of the string
c=d++d         -- c -> "----"
b=c++d         -- b -> "------" -> b has length 6
y=b++n         -- y -> 6 dashes plus newline "-------\n"

Dengan flag compiler diperbolehkan ada solusi 5x5:

Haskell, 5x5 (dengan flag -cpp compiler)

(>>)\
[1,2\
..5]\
"abc\
de\n"

Cobalah online!

-cppmemanggil preprocessor cpp yang memungkinkan garis lipat melalui \.

— nimi
sumber
Apa yang terjadi pada 7x7? Tampaknya baik-baik saja, tetapi saya tidak terbiasa dengan Haskell.
— Solomon Ucko
@SolomonUcko: Meskipun OP mengatakan bahwa kuadrat terbesar menang, semua orang mencoba untuk mendapatkan sekecil mungkin, karena itu sepele untuk membuat kotak besar dengan mengisi barang-barang yang tidak perlu (bahkan dalam aturan tantangan). Setelah 7x7 saya, saya menemukan solusi 6x6 jadi saya memperbarui jawaban saya.
— nimi
Oke, itu masuk akal. Saya kira Anda bisa memposting keduanya?
— Solomon Ucko
@SolomonUcko: tentu, tapi 7x7 pada dasarnya sama dengan 6x6, jadi tidak terlalu menarik.
— nimi
Benar. Sepertinya perubahan sebagian besar hanya mengubah nama variabel, menghapus titik koma, dan menghapus pernyataan tugas yang tidak perlu.
— Solomon Ucko
3

SOGL V0.12 , N = 3 2

H$
$Q

Coba Di Sini!

Baris pertama - H$artinya in the continuing lines replace $ with H, menghasilkan baris berikutnya HQ. Itu kemudian dieksekusi:

H   decrease POP (nothing on the stack so input (no input so 0)) - results in 0-1 = -1
 Q  output that without popping
    implicitly output POP as none of `tTpP` were called

Menemukan ini dengan memaksa paksa melalui semua program pada panjang 2 (seperti program apa pun ..\n..akan selalu turun ke program 2 karakter)

— dzaima
sumber
3

Python 2 , n = 6

print\
'\n'.\
join(\
['###\
###']\
*+~-7)

Cobalah online!

Bukan golf seperti itu, tapi ... Aku harus mengisi kekosongannya, bukankah begitu: P

— Khusus ASCII
sumber
Saya tidak berpikir ini dapat lebih lanjut golf ... karena printitu sendiri adalah 6 byte dan 1 byte '\' adalah paksaan terendah.
— officialaimm
Ya, saya maksudkan karena bisa di-golf hingga ~ 16 byte jika tidak ada batasan format sumber
— ASCII-satunya
1
@ resmi juga baik secara teknis Anda bisa membangun string "print"dan kemudian eval, tapi saya pikir Anda akan pergi terlalu jauh untuk masuk ke 5x5...
— Stephen
@LangkahHen oh yeah ... eval mungkin obat ...
— officialaimm
3

> <> , N = 3

"vn
:/^
ao/

Mencetak

110
110
118

Cobalah online , atau tonton di taman bermain ikan !

Ini agak sulit, jadi bersabarlah. Ikan mulai di sudut kiri atas, dan segera memasuki mode string. Ini mendorong kode "v" dan "n" ke stack, masing-masing 118 dan 110. Ikan kemudian membungkus dan memukul "lagi, keluar dari mode string. The vkemudian mengirimkan ikan ke bawah, dan /mencerminkan itu kiri ke :yang duplikat atas tumpukan: stack sekarang 118, 110, 110.

Ikan kemudian membungkus dan ^mengirimkannya dalam satu lingkaran:

  n
  ^
ao/

Lingkaran ini mencetak bagian atas tumpukan sebagai angka ( n), membungkus dan memantul, mendorong a = 10 = linefeed ke tumpukan, kemudian mencetaknya sebagai karakter ( o) dan memulai loop lagi. Ketika tumpukan kosong, nmenyebabkan kesalahan dan program berhenti.

Telah ditunjukkan dalam komentar bahwa berhenti dengan kesalahan agak tidak memuaskan. Karena itu saya memberi Anda alternatif yang berhenti secara alami, dalam kotak 4x4:

aa|v
no"/
lo~/
;!?/

Mencetak

/110
/110
/110
/110

Cobalah online!

— Bukan pohon
sumber
Apakah pencetakan something smells fishy...tidak masuk hitungan, karena secara teknis itu dicetak ketika kesalahan program (IIRC itu dicetak ke STDOUT).
— cole
@cole, saya cukup yakin itu mencetak ke STDERR, yang diabaikan secara default . Berhenti dengan kesalahan adalah cara yang sangat umum untuk menghentikan program> <>. Jika Anda benar-benar menginginkan kode bebas kesalahan, saya dapat memasukkannya dalam kotak 5x5: Coba online!
— Bukan pohon
1
Saya pasti lupa>> <>. Saya suka kedua solusi, omong-omong (dan saya pikir 3x3 sangat pintar).
— cole
2

CJam, n = ∞

Versi root: n = 2

AN
BN

Cobalah secara Online

Cetakan

10
11

Dapat diperluas ke sembarang n dengan menambahkan angka ke setiap baris. Misalnya:

n = 11

123456789AN
123456789AN
123456789AN
123456789AN
123456789AN
123456789AN
123456789AN
123456789AN
123456789AN
123456789AN

Cetakan

12345678910
12345678910
12345678910
12345678910
12345678910
12345678910
12345678910
12345678910
12345678910
12345678910
12345678910

Cobalah secara Online

— geokavel
sumber
1

Perl 5 , 4x4

(say
1111
)for
1..4

Cobalah online!

Dibutuhkan -M5.010pada baris perintah.

— m-chrzan
sumber
BTW, apakah cmdlinearg -M5.010memiliki efek yang sama dengan baris dalam file yang berbunyi use 5.010;?
— iBug
@ iBug biasanya use 5.010atau -M5.010dapat dianggap sebagai gratis, karena sebagian besar fitur yang diimpor olehnya dapat diakses dengan menjalankan skrip via perl -Ealih-alih perl -eyang panjangnya sama.
— Dom Hastings
1
Jangan berpikir ada panjang 3 var (bukan berarti saya bisa melihat di dalam perlvarpula) kalau tidak, Anda bisa mendapatkan 3x3 dengan sesuatu seperti ini ... Akan bermain dengan ini hari ini sekalipun!
— Dom Hastings
1

brainfuck , N = 6

++++++
++++>-
--->++
++++[<
......
<.>>-]

Bisa dibilang ini tidak valid karena saya sewenang-wenang memilih output char menjadi 3 codepoint lebih rendah untuk memperbaiki sqaure ...

Cobalah online!

— Dom Hastings
sumber
1

Python 3 , N = 13 (181 byte)

print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)
print("#"*13)

Cobalah online!

Saya tidak melihat mengapa ini tidak valid, karena tidak ada aturan yang memaksa saya untuk tidak menggunakan teknik ini (saya pikir). Ini mencetak grid 13x13 gurita.

— Tuan Xcoder
sumber
1

Aceto , 3x3

Masukkan nol implisit ke float ( 0.0), duplikat, cetak, baris baru, duplikat, cetak, baris baru, cetak, baris baru.

dpn
npp
fdn

Versi lama yang mungkin tidak valid:

Aceto dibuat untuk tantangan semacam ini; semua program adalah kotak, setidaknya secara internal. Ini mungkin atau mungkin tidak valid, karena dalam output, baris terakhir tidak berakhir dengan linefeed. Kami hanya menghitung 2 ^ 7, nyalakan mode sticky, dan mencetak tiga kali dengan baris baru di antara.

pnp
kFn
27p
— L3viathan
sumber
1

Gaia , 3 x 3

3/ṣ
ṙ×↑
9:⇈

Cobalah online!

Penjelasan

9    Push 9
 :   Copy it
  ⇈  Call the function above
ṙ    String representation of 9
 ×   Repeated 9 times
  ↑  Call the function above
3/   Split into chunks of 3
  ṣ  Join with newlines

Gaia, 2 x 2

gp
Ø↑

Saya tidak yakin apakah ini valid karena ini adalah quine kecurangan ( Øgmembaca file sumber program).

— Kucing Bisnis
sumber
1

PHP, n = ∞

Saya tidak tahu apakah ini celah, tapi ini 2versinya:

aa
aa

Cetakan

aa
aa

Cobalah online!

Dengan n = 10

aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa
aaaaaaaaaa

Cobalah online!

Dapat diperpanjang ke nomor apa pun.

— LP154
sumber
5
(Saya tidak berpikir itu celah, saya pikir itu adalah contoh mengapa kita tidak melakukan bowling kode).
— Magic Octopus Mm
1

Python 3 , n = 6

print\
('\n'\
.join\
(['$$\
$$$$'\
]*+6))

Cobalah online!

Hampir sama dengan jawaban Python 2, hanya dengan parens: /

Saya bisa membuatnya lebih berbeda jika ada yang mau: P

— Khusus ASCII
sumber
1

TI-BASIC, N = 2

Disp Xmax
Disp Xmax

Perhatikan bahwa Disp(termasuk spasi) dan Xmaxmasing-masing satu karakter. Karena Xmax adalah 10 secara default, outputnya adalah:

10
10
— Khuldraeseth na'Barya
sumber
0

Excel VBA, n = 15

Deklarasi subrutin yang menggunakan variabel input kosong, (untuk output) dan output untuk rentang [A1], melalui kotak pesan dan jendela langsung VBE, dan melalui variabel input

Sub$A(n):s="1|"
s=s+"2"+"|"+"3"
s=s+"|"+"4"+"|"
s=s+"5"+"|"+"6"
s=s+"7|8|9|0|1"
s=s+"2|3|4"+"|"
s=s+Chr(51+9-7)
tu=Split(s,"|")
var=Join(tu,"")
[B1]=var+vbCrLf
o=[Rept(B1,15)]
MsgBox$o,0,"hi"
Let[A1]=CStr(o)
Debug.Print[A1]
n=o:End:End$Sub

Autoformats di atas untuk 

Sub A(n): s = "1|"
s = s + "2" + "|" + "3"
s = s + "|" + "4" + "|"
s = s + "5" + "|" + "6"
s = s + "7|8|9|0|1"
s = s + "2|3|4" + "|"
s = s + Chr(51 + 9 - 7)
tu = Split(s, "|")
Var = Join(tu, "")
[B1] = Var + vbCrLf
o = [Rept(B1,15)]
MsgBox$ o, 0, "hi"
Let [A1] = CStr(o)
Debug.Print [A1]
n = o: End: End Sub

dan output 

123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
123456789012345
— Taylor Scott
sumber
0

Pesona Rise , n = ∞ (min 7x7)

"'.<~SD|
"'.<~SD|
"'.<~SD|
"'.<~SD|
"'.<~SD|
"'.<~SD|
"'.<~SD|
k@."0<Ra

Cobalah online!

Sangat memanfaatkan kemampuan Runic untuk menangani beberapa petunjuk instruksi secara bersamaan. Apa yang digandakan quine? Kenapa, satu quine dua kali lebih lama.

Semua .perintah adalah bagaimana ekspresi quine dasar "'<~S@|dapat diperluas menjadi lebar sewenang-wenang. Salinan tambahan dari quine memperluas kotak secara vertikal. Baris baru dan output ditangani oleh baris terakhir, menyalurkan semua IP quine ke ekspresi terminator tunggal, mengikuti Rak@, yang mendorong karakter baris baru, lalu membuang seluruh tumpukan bagian atas ke bawah ke output. Baris terakhir itu sendiri juga menghasilkan garis keluaran,.@kaR<00 untuk mempertahankan ukuran struktur yang diperlukan. Sebagai baris terakhir yang keluar terlebih dahulu, tidak ada baris baru yang memimpin atau tertinggal.

Ada quines yang lebih pendek (yaitu '<~@|"), namun baris terakhir sulit dibatasi hingga 7 karakter, atau tidak dapat menghasilkan output dengan lebar yang benar ( @"<Rakpanjang 6 karakter, tetapi hanya menghasilkan 5 karakter).

Saya juga berusaha untuk mengkode kotak terkecil yang mungkin. Ini adalah yang terbaik yang bisa saya lakukan.

Pesona Rise , n = 6

\>1CYS
\:$1Xk
\:$S:$
\S:$S:
\$S:$S
\:$q:@

Cobalah online!

Ulangi bagian atas tumpukan berulang-ulang, cetak, dan tukar dua item teratas untuk mencetak 100000enam kali dengan 5 baris baru terjalin.

Dan kemudian, karena saya bisa:

Pesona Rise , n = 9

\>311+6Xk
\w421+akw
\"'{~Sak"
\"@|."'"S
\q:1K1K1K
\1K1K1K1K
\1K1K1KE:
\E:E:E:1K
\311++*E;

Cobalah online!

Program 9x9 kuadrat yang menghasilkan kuadrat 9x9 (dengan newline terkemuka).

Ini dilakukan dengan membuat quine 9-byte sebagai string dan kemudian Emengujinya 4 kali, kemudian mengalikan string dengan 5 ( "abc"*3-> "abcabcabc") dan Evaling sekali lagi untuk 5 salinan terakhir. Ini dilakukan dengan cara ini untuk mengisi kotak 9x9 tepat ke tepi.

— Draco tidak lagi percaya pada SE
sumber
0

Bahasa Wolfram (Mathematica) , n = 5

Do[1+
Echo[
+100*
+100]
,5*1]

Keluaran

>> 10000
>> 10000
>> 10000
>> 10000
>> 10000

Asumsikan bahwa Anda tidak menghitung >>itu akan menjadi yang terpendek karena hanya fungsi pencetakan yang Printdan Echo. Anda juga harus memasukkan setidaknya 1 karakter setelah fungsi untuk memanggilnya.

Map[1+
Print@
#+10&,
Array[
9^6+1+
#&,6]]

Cobalah online!

Keluaran

531443
531444
531445
531446
531447
531448

dengan baris baru yang tertinggal

n = 7

Print/@
Array[0
+0+0+0+
0+0+0+0
+0+0+0+
1234557
+10&,7]

Cobalah online!

Keluaran 

1234567
1234567
1234567
1234567
1234567
1234567
1234567

dengan baris baru yang tertinggal

— buttercrab
sumber
0

Perl 5, 9x9

for(1..$=
/7){$qq=(
$q=$_)**7
;for($qq%
7..$q/7){
map{print
qq,qqq,,,
qq,qqqqqq
,,}0..2}}

Penjelasan

forLingkaran luar melewati urutan 1 .. ($= / 7). $ = adalah 60, jadi loop berjalan dari 1 ke lantai 60/7, yaitu 8.

Pernyataan pertama di loop luar $qq = ($q=$_)**7,, memberikan variabel $qnilai indeks $_loop, dan memberikan $qqnilai $qpada kekuatan ketujuh.

Kemudian muncul lingkaran dalam, yang melebihi urutan $qq % 7 .. $q / 7( %adalah modulo).

For this value of $q,      the inner loop is over this sequence:
          1                             1 .. 0
          2                             2 .. 0
          3                             3 .. 0
          4                             4 .. 0
          5                             5 .. 0
          6                             6 .. 0
          7                             0 .. 1
          8                             1 .. 1

Jadi loop dalam berjalan total tiga kali: dua kali ketika indeks loop luar adalah 7, dan satu kali ketika indeks loop luar adalah 8.

Loop dalam melakukan map{...} 0..2yang merupakan loop lain, kali ini di atas urutan 0 .. 2, sehingga melakukan tiga kali berikut:

print
qq,qqq,,,
qq,qqqqqq
,,

The qqs adalah operator double-kutipan , jadi ini hanya cetak qqqdan qqqqqq<newline>.

Jadi, outputnya adalah

qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq
qqqqqqqqq

Cobalah online.

— msh210
sumber
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