Eww, byte-byte itu kotor

86

Tulis program atau fungsi yang, ketika diberi string, memfilter sebanyak mungkin byte berbeda dan mengembalikan string yang telah dibersihkan. Namun, karena program Anda membencinya, tidak ada byte ini yang dapat ditampilkan dalam kode Anda sendiri.

Skor Anda akan menjadi jumlah byte berbeda yang disaring oleh program Anda dari input, dengan semakin tinggi semakin baik. Ini adalah skor maksimal 255 (karena program Anda harus minimal satu byte). Tiebreaker adalah panjang kode Anda, dengan lebih rendah lebih baik.

Misalnya, jika program Anda memfilter byte 0123456789, ia menerima skor 10, tetapi program Anda sendiri tidak dapat mengandung byte ini.

Aturan

  • Bytes berarti oktet.
  • Anda juga memiliki opsi untuk mengambil input sebagai daftar bilangan bulat, dengan nilai mulai dari 0 hingga 255. Ini sesuai dengan byte yang setara.
    • Output Anda harus dalam bentuk yang sama dengan input Anda
  • Tidak membaca kode sumber Anda
  • Kode Anda harus tidak kosong
  • Ya, saya tahu akan ada jawaban Bahasa / Unary. Tapi setidaknya golf tolong?;)

Edit Aturan:

  • Anda dapat memilih untuk mengabaikan byte, misalnya jika byte tersebut tidak dapat dibedakan dari byte yang diakhiri untuk string atau untuk EOF. Namun, ini berarti Anda tidak dapat menggunakannya dalam kiriman Anda, juga tidak menghitung skor Anda. Jika Anda memilih untuk melakukannya, skor maksimal Anda adalah 254, tetapi Anda tidak harus menangani byte tersebut di input Anda.
code-challenge  restricted-source  self-referential 
— Jo King
sumber
1
Apakah OK jika fungsi tidak berfungsi jika string berisi null byte (\ 0)? Karena C menggunakan string terminasi nol, suatu fungsi tidak dapat mengetahui apakah itu akhir dari string atau hanya byte nol.
— wastl
4
"Bytes berarti byte oktal." Apakah maksud Anda Octet? Oktal adalah cara menulis angka, tiga bit sekaligus sehingga tidak selalu sejalan dengan batas byte.
— Kevin
1
tampaknya hanya meminta jawaban di brainfuck
— Jasen
1
@ cmaster Untuk orang-orang yang tidak dapat melihat tulisan yang dihapus: Ada beberapa upaya brainfuck, keduanya gagal karena mereka tidak dapat membedakan byte NUL dari EOF.
— Ørjan Johansen
3
@ ØrjanJohansen Saya telah menambahkan aturan yang dapat membuat Anda mengabaikan byte (untuk tujuan EOF). Ini seharusnya tidak terlalu dapat disalahgunakan, karena itu juga menurunkan skor maks Anda, dan itu membuat pertanyaan lebih inklusif.
— Jo King

Jawaban:

34

Python 2 , skor 249, 1732 byte

c="%c%%c%%%%c%%%%%%%%c"
ex=c==c
ee=c==""
exec"e=%x%%x"%ex%ex
exec"e%%%%%%%%=%x%%x%%%%x"%ee%ex%ee
exec"ee=%x%%x"%e%ee
exec"ee%%%%=%x%%x"%ex%e
exec"e=%x%%x"%ee%e
exec"ec=ex%cex"%e
exec"xe=ec%cec"%e
exec"xx=xe%cxe"%e
exec"xc=xx%cxx"%e
exec"ce=xc%cxc"%e
exec"cc=ce%cce"%e
exec"eee=xx%cec"%e
exec"cee=ce%cec"%e
exec"exe=ce%cex%%cxe"%e%e
exec"xxe=ce%cxx"%e
exec"cxe=ce%cex%%cxx"%e%e
exec"ece=ce%cec%%cxe%%%%cxx"%e%e%e
exec"xce=ce%cex%%cxe%%%%cxx%%%%%%%%cxc"%e%e%e%e
exec"cce=cc%cex%%cce"%e%e
exec"eex=cc%cex%%cec%%%%cce"%e%e%e
exec"xex=cc%cex%%cxe%%%%cce"%e%e%e
exec"cex=cc%cec%%cxe%%%%cce"%e%e%e
exec"exx=cc%cxx%%cce"%e%e
exec"xxx=cc%cex%%cxx%%%%cce"%e%e%e
exec"cxx=cc%cec%%cxx%%%%cce"%e%e%e
exec"ecx=cc%cxe%%cxx%%%%cce"%e%e%e
exec"xcx=cc%cec%%cxe%%%%cxx%%%%%%%%cce"%e%e%e%e
exec"ccx=cc%cex%%cec%%%%cxe%%%%%%%%cxx%%%%%%%%%%%%%%%%cce"%e%e%e%e%e
exec"eec=cc%cxc%%cce"%e%e
exec"xec=cc%cec%%cxc%%%%cce"%e%e%e
exec"cec=cc%cex%%cec%%%%cxc%%%%%%%%cce"%e%e%e%e
exec"exc=cc%cxe%%cxc%%%%cce"%e%e%e
exec"xxc=cc%cex%%cxe%%%%cxc%%%%%%%%cce"%e%e%e%e
exec"cxc=cc%cec%%cxe%%%%cxc%%%%%%%%cce"%e%e%e%e
exec"ecc=cc%cxx%%cxc%%%%cce"%e%e%e
exec"""x=""
"""
exec"x%c=c%%xex%%ecc%%xex%%eex"%e
exec"x%c=c%%cee%%cee%%ece%%cxx"%e
exec"x%c=c%%ccx%%xxx%%xcx%%xxe"%e
exec"x%c=c%%eex%%exx%%xec%%xxe"%e
exec"x%c=c%%xex%%cxc%%cce%%ecx"%e
exec"x%c=c%%xxe%%eex%%cxe%%cxe"%e
exec"x%c=c%%cex%%ccx%%xec%%ce"%e
exec"x%c=c%%eex%%ce%%xxx%%xcx"%e
exec"x%c=c%%ce%%eex%%ecc%%ece"%e
exec"x%c=c%%cec%%eec%%ecx%%xxx"%e
exec"x%c=c%%exc%%xxe%%cxe%%cxe"%e
cx="""eec
xec
xxx
xcx
exc
cee
cee
ece
cxx
ccx
xxx
xcx
xxe
xex
ce
cex
ccx
xec
ce
xex
ce
xxx
xcx
ce
xxx
xcx
eec
xxc
exc
xxe
cxe
xxx
cex
ce
xex
ce
xxx
xcx
cee
cee
cee
eee
xex
ecc
xex
eex
cee
xce
exe
cee
cee
cee
cxe"""
exec"exec%cx"%ce

Cobalah online!

Menghapus semuanya kecuali exc%="baris baru. Pembuatan kode adalah milik xsot . Saya ragu ini dioptimalkan, jadi ada banyak byte untuk disimpan di sini!

— Lynn
sumber
26

Haskell, skor 249 250, 1088 335 byte

(!:)((=:):(!=))=(((!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(:):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(:):(!):(!):(!):(!):(!):(!):(:):(:):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(!):(:):(!):(!):(:):(=!))!!(=:))(=:)((!:)(!=))
(!:)(=:)=(=:)
(=:)!(!=)=(!=)
(=!)=(!):(=!)

Menentukan fungsi !:yang mengambil daftar bilangan bulat dan memfilter semua kecuali 10,33,40,41,58,61, kode ASCII dari \n ! ( ) : =.

Cobalah online!

Cara kerjanya: Pertama mari kita ganti nama fungsi dan parameter menjadi nama waras:

f (x:xs) = (listOfFunctions !! x) x (f xs)                   -- (!:)
f x = x

listOfFunctions = d:d:d:d:d:d:d:d:d:k:d:d ... : infiniteDs   -- inlined
infiniteDs = d : infiniteDs                                  -- (=!)

k      = (:)                                                 -- inlined
d x xs = xs                                                  -- (!)

Gagasan utamanya adalah memiliki daftar dua fungsi yang berbeda ( listOfFunctions), satu untuk menyimpan elemen ( k) dan satu untuk menjatuhkannya ( d). Daftar diindeks oleh elemen saat ini dari daftar input ( x) dan fungsi yang dipilihnya menentukan apakah akan menyimpan atau menjatuhkan elemen. Pada indeks 0 yang kami miliki d, karena kami ingin menjatuhkan 0s, yang pertama kadalah pada indeks 10, karena kami ingin mempertahankan 10s (baris baru). Keduanya kdan dmengambil dua parameter: xdan hasil dari panggilan rekursif dengan sisa daftar ( xs). kprepends xke panggilan recursice dan dhanya mengembalikan panggilan recursive.

Daftar literal fungsi berakhir pada indeks 61 (char =, yang terakhir kdalam daftar) dan diikuti oleh jumlah tak terbatas d. Ini tidak hanya menyimpan banyak eksplisit d, tetapi juga mencegah kita dari harus mengakhiri daftar yang terbatas dengan []yang memerlukan karakter tambahan.

Sunting: terima kasih kepada @ Ørjan Johansen untuk skor +1 dan -753 byte.

— nimi
sumber
1
Dengan memasukkan fungsi dalam daftar alih-alih Bools Anda dapat menyingkirkan |untuk skor 250, 335 byte . Juga mendefinisikan sinonim untuk repeat (!)mempersingkat daftar (secara drastis, karena |jauh lebih besar dari karakter yang dikecualikan terbesar kedua.
— Ørjan Johansen
Kalau dipikir-pikir, fungsi untuk menyingkat beberapa dari (!):sekuens panjang itu mungkin juga akan membantu.
— Ørjan Johansen
@ ØrjanJohansen: ya, tetapi sublist harus terbatas, jadi Anda perlu cara untuk membuat daftar kosong hanya dengan !():=. Mengekstrak []dari daftar yang ada, misalnya daftar input, tidak akan berfungsi karena memiliki tipe [Int], tetapi kita perlu [a->[a]->[a]].
— nimi
Bisakah Anda jelaskan cara kerjanya? !adalah curry snd, dan =!merupakan daftar yang tak terbatas dari ini, tetapi hanya itu yang bisa saya mengerti dari ini.
— Michail
1
@nimi saya berarti fungsi dalam Selain untuk (=!), sesuatu seperti (!=)(=:)=(!):(!):(!):(!):(!):(=:)atau (lebih tinggi tingkat, dapat dilalui ((!):)atau bagian dari dirinya sendiri) (!)!=(=:)=(!)((!)((!)((!)(=:)))). Banyak opsi untuk mengubah. Jumlah pengulangan, argumen apa yang kedua (atau bahkan ketiga) jika ada, dan bahkan jika itu lebih optimal untuk kompresi untuk menggunakan \natau ;(panjang blok 10 22 6 16 2vs. 33 6 16 1).
— Ørjan Johansen
20

JavaScript (ES6), skor: 242 (142 byte)

Pendekatan yang agak naif menggunakan array byte untuk I / O.

t=>t.filter(t=>'f'>'fffffffffffffffffffffffffffffffffffffffeeeffffeffffffffffffffeeffffffffffffffffffffffffffffefefffffffeeffeffefffffefe'[t])

Cobalah online!

Bagaimana?

14 karakter yang tidak difilter adalah '().=>[]efilrt. Mereka ditandai dengan edalam string pencarian. Untuk karakter di atas t(ASCII kode 116) yang tidak didefinisikan dalam string ini, 'f'>undefinedadalah palsu .

— Arnauld
sumber
14
Saya berharap salah satu dari ini akan panjangnya persis 144 byte. Ini layak mendapat kredit ekstra karena menjadi salah satu solusi kotor .
— Jeff Bowman
Deskripsi mengatakan "ketika diberi string" ...
— Yair Rand
2
@YairRand Dan juga tertulis "Anda juga memiliki opsi untuk mengambil input sebagai daftar bilangan bulat".
— Arnauld
1
Saya pikir solusi ini mundur - sepertinya idealnya satu-satunya karakter yang harus di-output adalah karakter yang sebenarnya digunakan dalam kode, sementara yang lainnya disaring. Kabar baiknya adalah bahwa solusi ini dapat dengan cepat diadopsi untuk bekerja seperti itu, sementara mencukur dua byte off: t=>t.filter(t=>'f'>'fffffffffffffffffffffffffffffffffffffffeeeffffeffffffffffffffeeffffffffffffffffffffffffffffefefffffffeeffeffefffffefe'[t]). Inilah pernyataan tes TIO:console.log(f([...Array(256).keys()]).map(c => String.fromCharCode(c)))
— Scott Hamper
2
@Arnauld Saya pikir Anda telah menakuti semua kontestan JS yang layak lainnya dengan supergolf cepat Anda ...
14

Shell POSIX , skor 249, 18 byte

tr -cd \\\\\ cdrt-

Cobalah online!

trPerintah sederhana yang menghapus semua karakter kecuali -\cdrtdan spasi. Diperlukan empat backslash karena shell dan trperintah menggunakan backslash lolos. Garis miring terbalik kelima lolos dari karakter spasi berikut.

Jika tr -cddianggap sebagai bahasa pemrograman, seseorang dapat menulis progam byte tunggal dengan skor 255.

— nwellnhof
sumber
Ya, saya kira. Itu punya ekspresi reguler, yang cukup kuat.
— wizzwizz4
2
@ wizzwizz4 trmemiliki kelas karakter seperti yang digunakan dalam ekspresi reguler, tetapi tidak ada ekspresi reguler penuh itu sendiri.
— Trauma Digital
Saya tidak mengerti untuk apa garis miring terbalik, di sini. Saya pikir itu akan berhasil tanpa mereka?
— David Conrad
1
@ Davidvidon Memang, tapi kemudian tidak menghemat ruang. Maka Anda perlu 4 garis miring terbalik untuk garis miring terbalik.
— wizzwizz4
3
Saya mencukur satu byte, dengan mengorbankan kepatuhan POSIX, dengan tr -cd \ cdrt\\-\ Coba online!
— wizzwizz4
14

C (gcc) , skor 232 235 239 241 242, 260 407 352 249 243 249 byte

fn(int*f,int*i,int*n,int**t){if(f==i)if(*t=n){}if((f==i)==('+'=='*')){if((*f==',')+(*f=='\'')+(*f=='(')+(*f==')')+(*f=='*')+(*f=='+')+(*f=='=')+(*f=='\\')+(*f=='f')+(*f=='i')+(*f=='n')+(*f=='t')+(*f=='{')+(*f=='}'))if(*n++=*f){}if(fn(++f,i,n,t)){}}}

Cobalah online!

Sebuah fungsi yang mengambil pointer ke awal dan akhir array int (di mana akhir adalah karakter pertama yang tidak termasuk), pointer ke buffer dan pointer ke pointer int lainnya. Ini menulis hasilnya ke buffer dan pointer akhir hasilnya ke pointer terakhir.

— wastl
sumber
1
Jika itu membantu Anda, tantangannya telah diedit sehingga sekarang diizinkan untuk mengabaikan satu nilai byte tertentu, katakanlah untuk string yang diakhiri dengan NUL. Itu memang mengurangi skor.
— Ørjan Johansen
12

Jelly , skor 254 (4 byte)

f⁾f⁾

Cobalah online!

⁾xy adalah singkatan untuk “xy”(string dua karakter).

Kami filter string input ke hanya karakter yang terjadi di “f⁾”.

— Lynn
sumber
2
Heh, saya sudah menyiapkan jawaban f⁾⁾ftetapi memutuskan untuk mengajukan pertanyaan tentang mengambil string Unicode sebelum memposting.
— Jonathan Allan
10

Ruby -p, skor 248 (8 byte unik / 483 byte)

eval""<<11+11+11+1+1+1<<11+11+11+11+11+11+11+11+1+1+1+1+1+1+1<<11+11+11+11+1+1<<111+1+1+1+1+1<<111+1+1+1<<11+11+11<<11+11+11+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1<<111+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1<<11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1<<11+11+11+11+1+1+1+1+1<<11+11+11+1<<11+11+11+1+1+1+1+1+1+1+1+1+1<<11+11+11+11+11+1+1+1+1+1<<11+11+11+1+1+1+1+1+1<<11+11+11+11<<11+11+11+1+1+1+1+1+1<<11+11+11+1+1+1+1+1+1

Cobalah online!

— GB
sumber
2
Itu brilian. :)
— David Ljung Madison Stellar
10

Python 2 , Skor 244 245 246, 13390 1575 byte

Mengambil daftar bilangan bulat

exec'%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c%c'%(111+1,111+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1,111+1+1+1+1+1,11+11+11+11+11+11+11+11+1+1+1,111+1+1+1+1+1+1+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1,11+11+11+11+11+11+11+11+11+11+1,111+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,111+1+1+1+1+1+1+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1,111+1,111+1+1+1+1+1+1,111+1+1+1+1+1,11+11+11+1+1+1+1+1+1+1,11+11+11+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,111+1+1+1+1+1+1+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1,11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1,111+1,11+11+11+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+11+11+1,111+1+1+1,11+11+11+11+11+11+11+11+11+1,11+11+11+1+1+1+1+1+1+1+1+1+1+1,11+11+11+1,11+11+11+11+11+11+11+11+11+1+1,111+1+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+1+1+1+1+1+1+1+1+1+1+1,11+11+11+1+1+1+1+1+1,11+11+11+1+1+1+1,11+11+11+1+1+1+1+1+1+1+1+1+1,11+11+11+1+1+1+1+1+1+1,11+11+11+1+1+1+1+1+1+1+1,11+11+11+11+1+1+1+1+1,11+11+11+1+1+1+1+1+1+1+1+1+1+1,11+11+11+1,11+11+11+1+1+1+1+1+1+1+1,11+11+11+11+11+11+11+11+1+1+1+1+1)

Cobalah online!

Ini mengevaluasi ke baris kode berikut:

print[x for x in input()if x in map(ord,"exc'%+()1,")]

Python 2 Skor 248, byte∼252

Jawaban ini jelas merupakan jawaban teoretis. Strukturnya adalah

exec'<2**51 times %>c<2**50 times %>c ... %%c%c'%<112 times -~>0%<114 times -~>0% ... %<41 times -~>0%<93 times -~>0

Secara teori ini akan mengeksekusi sama dengan:

print[x for x in input()if x in map(ord,"exc'%-~0")]

Python 3 , Skor 240 241, 54 byte

+1 terima kasih kepada Jonathan Allan .

lambda a:[i for i in a if i in b""" ":[]abdfilmnor"""]

Cobalah online!

— ovs
sumber
Anda bisa menghilangkan kebutuhan untuk \dalam versi Py 3 Anda dengan menggunakan tanda kutip tiga b''' ':[]abdfilmnor'''. Dalam Python 2 Anda bisa melakukan program lengkap dalam nada yang sama untuk 242:, print(''.join(p for p in input() if p in ''' '().fijnoprtu'''))meskipun tidak sebagus exec.
— Jonathan Allan
10

Bersihkan , skor 247, 234 213 208 byte

-5 byte berkat Ørjan Johansen

== =t
t['\'':t]=['\'': ==t]
t['\\':t]=['\\': ==t]
t[':':t]=[':': ==t]
t['[':t]=['[': ==t]
t[']':t]=[']': ==t]
t['t':t]=['t': ==t]
t['=':t]=['=': ==t]
t[' ':t]=[' ': ==t]
t['
':t]=['
': ==t]
t[tt:t]= ==t
t t=t

Cobalah online!

Menggunakan fungsi rekursif pencocokan pola untuk menghapus karakter. Bahkan tidak perlu StdEnv.

— Suram
sumber
2
Ini dapat langsung diterjemahkan ke fungsi Haskell dengan 7 karakter unik. Skor yang sama dengan jawaban saya, tetapi jauh lebih sedikit byte ( Coba online! ). Bagus!
— nimi
@nimi Itu bisa digunakan =\ sebagai gantinya ===.
— Ørjan Johansen
Saya pikir Anda ingin beralih tdan ttdi baris terakhir kedua.
— Ørjan Johansen
Ini menghemat byte untuk mengubah nama ==ke ttapi tetap ==sebagai sinonim untuk itu.
— Ørjan Johansen
@ ØrjanJohansen Tangkapan bagus, terima kasih!
— Surous
7

05AB1E , skor: 252 253 (  4  3 byte berbeda digunakan; total 8 byte )

„ÃJ„„JJÃ

Cobalah online.

Penjelasan:

„ÃJ        # Push the String "ÃJ"
   „„J     # Push the string "„J"
      J    # Join them together: "ÃJ„J"
       Ã   # Only keep these three characters from the (implicit) input
           # (and output the result implicitly)

Perhatikan bahwa urutan ÃJdan „Jdalam string 2-char penting, karena „juga digunakan untuk kata-kata kamus , di mana setiap dua karakter adalah kata kamus (kecuali untuk beberapa karakter tertentu seperti huruf, angka -, dan semacamnya). Jadi „JÃakan menjadi 'kata' J, serta kata kamus Ã+ karakter berikutnya (dalam hal ini „), yang ternyata adalah kata"causing" .

— Kevin Cruijssen
sumber
6
Dicoret 4 dengan spasi masih dicoret 4
— Jo King
7

Perl 5, skor 251 (5 byte berbeda, total 8.058 byte)

s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s>><><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s>><><<s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>>^s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<^>^>^^s>^><>^s<^>^>^^s>^>s>^s>^>e>^s>^>^>^s<^>^>^^s>^><>^s>^><>^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s^^^<<s^^^<<s>>><<s>>>^s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>>^s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>>^s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s^^^<<s>><<><<s>>>^s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>>^s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<^>^>^^s>^><>^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s>><<><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s^^^<<s>><<><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>>^s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s>><<><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>>^s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s^^^<<s>><><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<s<>e<><s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^<<s^^^^s^^^<<s>>><<s>>><<s>>><<s>>><<s>>>^s>>><<s>>><<s>>><<s>>><<s>>><e^s<^>e>ee<e^<see><>>>>^<^^<se^e^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^e^^^^^^^e^^>^^^^s^s^ss>^<^^^^s^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^s^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>^<^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^>>eeee^s<><<eee<e^<see><>>>^<^<^>^^^^s^s^s>^<^^^^^^^^^^^>^<^^^>>eeee

Cobalah online!

Menggunakan <>^essubset Turing-complete dari Perl . Kode di atas diperoleh dengan menjalankan print<>=~y<<>^es><>cdrmelalui konverter saya .

— Kotor
sumber
7

Brachylog , skor 249, 16 byte

{∈"{∈\\\"&}ˢ"&}ˢ

Cobalah online!

Tidak sepenuhnya yakin bagaimana ini bekerja dengan aturan, apa dengan Brachylog memiliki halaman kode khusus dan semuanya, tapi saya masih bisa menjelaskan cara kerjanya:

{                Start of inline predicate.
 ∈"              Input is a member of the string literal containing:
   {∈            the opening bracket, the member-of character,
     \\\"        backslash, quote,
         &}      ampersand, the closing bracket,
           ˢ"    and the superscript s.
             &}  Unify the input to the inline predicate with the output from the inline predicate.
               ˢ Output everything from the input that made it through the inline predicate.
— String yang tidak terkait
sumber
7

Oktaf , Skor 248 249 (50 byte)

Ada harus menjadi cara yang lebih baik ... dan ada! 

@(a)a('l'=='a'==all('l'=='a'==(a==('@al()''=')')))

Cobalah online!

Saring semuanya kecuali @al()'=. The allFungsi unggul lebih any, karena hanya menggunakan dua byte yang berbeda. Perhatikan bahwa any(...)sama dengan not(all(not(...))). Jadi, kita mulai dengan programnya

@(a)a(~all(a~=('@al~()''=')'))

Alih-alih ~( not) kita juga bisa menulis 0==. Tentu saja, itu berarti kita harus menyaring 0juga. Sebagai gantinya, perhatikan bahwa ungkapan berikut ini juga salah (nol)

'l'=='a'

Jika kompatibilitas MATLAB tidak menjadi masalah, saya dapat mencapai 47 byte

@(a)a((l='l'=='a')==all(l==(a==('@al()''=')')))
— Sanchises
sumber
7

Bahasa (dengan stty +brkint -ignbrk), skor 255, 3890951 byte

Program ini terdiri dari 3890951 NUL byte (menjadikan ini salah satu program Bahasa terpendek yang pernah ada; 3890951 byte mudah cukup kecil untuk muat di disk saya, jadi saya benar-benar menjalankan ini dalam juru bahasa Bahasa). OP ingin solusi Bahasa / Unary untuk golf, jadi di sini kita pergi. (Perhatikan bahwa Unary akan lebih lama karena membutuhkan penggunaan 0daripada mengizinkan penggunaan NUL.)

Perhatikan bahwa Bahasa tidak, terlepas dari apa yang tersirat dalam dokumentasinya, bertindak seperti yang dilakukan brainfuck; I / O bekerja sepenuhnya berbeda (sesuatu yang saya perhatikan ketika menguji program ini). Secara khusus, Bahasa menolak untuk mengambil input dari apa pun selain dari terminal, sehingga byte yang sedang disaring adalah byte mentah yang dikirim melalui koneksi terminal (perhatikan juga bahwa karena menyaring byte mentah, Anda tidak akan melihat Anda mengetik sama sekali). Dalam praktiknya, ini berarti bahwa program akan menyerap segala jenis input yang dikirim kepadanya kecuali untuk byte NUL (biasanya diketik sebagai Ctrl- @), yang akan digaungkan secara harfiah (pada saat itu, sebagian besar terminal akan mengabaikannya, karena byte NUL adalah terminal yang setara dengan instruksi NOP). Untuk memverifikasi bahwa program itu berfungsi, itu

Apa yang terjadi di EOF? Nah, jika terminal mengirim serangkaian byte, tidak ada cara untuk mengirim EOF; semua 256 byte yang mungkin diinterpretasikan secara harfiah, dan tidak ada lagi yang dapat Anda masukkan ke dalam aliran terminal. Namun, jika Anda kebetulan menggunakan terminal serial kuno, Anda dapat menekan tombol "break" pada terminal Anda untuk mengirim data yang salah kode dengan sengaja, memungkinkan kode yang mungkin ke-257; "break" ini adalah satu-satunya padanan EOF yang masuk akal, karena dikirim keluar dari band dan menunjukkan sesuatu selain data yang valid. Jika konfigurasi terminal Anda memiliki set flag "interrupt-on-break" (dan penerjemah Bahasa, sejauh yang saya tahu, tidak dapat mengubah pengaturan itu), mengirimkan sinyal istirahat akan menyebabkan penerjemah Bahasa akan crash, yang dengan mudah bertindak sebagai cara untuk menerapkan perilaku EOF yang diinginkan. Saya tidak yakin apakah ini pengaturan default (karena tidak ada yang benar-benar menggunakan terminal serial saat ini, pada dasarnya tidak pernah muncul), jadi saya menyebutkannya di header sebagai bagian dari spesifikasi penerjemah bahasa yang digunakan.

Penjelasan

  1110110101111100000111
001                       Initialise tape element 0 to -1
   110               111  While tape element 0 is nonzero:
      110   111              While tape element 0 is nonzero:
         101                    Read a byte from the terminal into tape element 0
               100           Output tape element 0
                  000        Add 1 to tape element 0

Loop dalam hanya akan keluar ketika NUL diketik di terminal; setelah ini, kami segera menggaungkan karakter yang diketik (yaitu NUL). Menambahkan 1 pada titik ini akan memastikan bahwa elemen pita 0 bukan nol lagi, sehingga loop luar tidak dapat keluar sama sekali (sampai input break crash interpreter), dan kami akan jatuh kembali ke loop dalam.

Golfiest menggunakan pengurangan untuk memasuki lingkaran luar, tetapi tambahan untuk terus mengulanginya; Selain itu memiliki penyandian yang lebih pendek, tetapi tidak dapat muncul pada awal program (karena penyandian akan terlihat seperti memimpin nol dan dengan demikian diabaikan).

— ais523
sumber
Kebetulan, saya cukup yakin saya bisa menjalankan program bahasa apa pun <4TB meskipun tidak memiliki disk sebesar itu. Juru bahasa tidak peduli tentang file yang berlubang.
— Joshua
truncatetidak membuat file jarang bagi saya (mungkin filesystem tidak mendukungnya?). Namun, sejauh yang saya tahu, penerjemah Bahasa referensi membaca file input satu per satu (!), Jadi jika program tidak mengandung karakter baris baru, program yang cukup panjang akan berakhir kehabisan memori yang tersedia. Tentu saja, ini bisa diperbaiki dengan juru bahasa baru.
— ais523
Tidak terpotong. Cari file baru ke satu byte sebelum akhir yang diinginkan dan tulis byte nol.
— Joshua
6

Retina 0.8.2 , 12 byte, skor: 250

[^]n\\\n[^]

Cobalah online! Menyaring semua karakter kecuali untuk baris baru, [, \, ], ^dan n. Meskipun karakternya [\]^berurutan, menggunakan rentang sebenarnya akan menghabiskan satu byte dan juga mengurangi skor saya.

— Neil
sumber
6

Japt , skor 249, 20 byte

f"[ fq\"[\\\\\\]]" q

Cobalah online!

— Khusus ASCII
sumber
Luis berhasil menemukan solusi optimal tetapi Anda dapat meningkatkan skor Anda dengan oQ+"+oQ"Qatau hanya ootetapi itu hanya variasi pada solusi Luis.
— Shaggy
Haha, tbh saya terburu-buru yang ini dan kehabisan waktu kemarin malam, dan imo lebih pendek dan semakin dekat dengan solusi luis: P
— ASCII-satunya
4

PHP, skor 234, 58 62 byte

<?=preg_replace("_[^\"$(),;<=?[\]^\_\\\\aceglnpr]_","",$argn);

Jalankan sebagai pipa dengan -nFatau coba online .

— Titus
sumber
4

Ruby -paF[^$_=F*'], skor 250, 8 byte

$_=$F*''

Saya tidak yakin sama sekali ini legal di bawah aturan situs saat ini untuk flag-command-line, karena "flag" di sini adalah semacam kode yang meneruskan yang menyertakan byte terlarang. The Fbendera mendefinisikan regex pemisah masukan yang terdiri dari semua karakter tidak dalam kode yang tepat. Kode yang tepat mengatur output ke gabungan semua catatan input.

— histokrat
sumber
4

MATL , Skor 252

t't''m)'m)

Cobalah online!

Penjelasan (untuk masukan input)

t         % Duplicate input. 
          % Stack: {'input', 'input'}
't''m)~'  % Push the string t'm)~ 
          % Stack: {'input', 'input', 't'm)~'}
m         % 'ismember' to filter
          % Stack: {'input', [0 0 0 0 1]}
)         % Index into input.
          % Stack: {'t'}
          % Implicit display.
— Sanchises
sumber
3

K, skor 246, 23 byte

{x@&~x in"\"~ in@&{x}"}

{..} adalah lambda dengan arg x

dibaca sebagai 'mengembalikan x di tempat bukan x dalam string'

String berisi \ "~ di @ & {x} (sepuluh byte yang digunakan dalam program)

— J. Sendra
sumber
3

sfk , skor 239, 133 byte

+xed -i -case ixixi x+x+x xexex xdxdx x-x-x xixix xcxcx xaxax xsxsx xbxbx xyxyx xtxtx x"x"x x\[x\[x x\]x\]x x\\x\\x "x x x" x[byte]xx

Cobalah online!

Melakukan penggantian pada input (ditulis sebagai [delim][from][delim][to][delim]) mengubah semua karakter yang digunakan dalam program untuk diri mereka sendiri, yang menghilangkan posisi karakter dari pertimbangan untuk input ke penggantian akhir x[byte]xxyang memetakan semua byte ke string kosong.

— Suram
sumber
3

JavaScript, skor 250, 95573 59273 byte

Solusi JS golf ringan yang kemudian dijalankan melalui algoritma JSFuck . Banyak byte, tetapi nilainya bagus.

Asli:

a=t=>t.replace(/[^![\]+()]/g,'')

Render JSFuck adalah 59273 karakter:

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— tschwab
sumber
2
s=>s.replace(/[^![\]+()]/g,'')harus bekerja
— ASCII
Ya, itu sangat signifikan. Ide bagus. Saya percaya bahwa tidak peduli bagaimana pun, ia akan berada di urutan ribuan byte.
— tschwab
3

brainfuck , Nilai: 248, 162 byte

,[>---[----------->--<]>-[>->->->-->------->-->-------[<<]>-]>--->-->->--->------------->->-----------[<]<<[->>>->->->->->->->-<<<<<<<<<<]>>>[>]>[[>]<[->-<]>.>],]

Cobalah online!

Biasanya saya tidak menjawab pertanyaan saya sendiri, tetapi orang-orang tampaknya telah membaca halaman profil saya, terutama di mana katanya If someone comments on a question "I wish there was a brainfuck solution", I feel obliged to provide one.

-<>[],.Byte yang difilter adalah dan mengabaikan byte NUL, karena tidak dapat dibedakan dari EOF. Ini sedikit lebih lama dari biasanya, karena saya sengaja menghindari menggunakan +untuk mendapatkan skor yang sedikit lebih baik. Meski begitu, saya mungkin bisa bermain golf bagian generasi nomor untuk menghemat beberapa byte.

— Jo King
sumber
1
Baik kiriman C dan Bahasa sudah disesuaikan secara khusus dengan kebutuhan untuk membedakan NUL dari EOF. Mungkin menggunakan BF 16-bit dengan konvensi EOF yang berbeda?
— Ørjan Johansen
3

Spasi , skor: 253 (3 byte berbeda digunakan, total 97 byte)

[N
S S N
_Create_Label_LOOP][S S S N
_Push_0][S N
S _Duplicate_0][T   N
T   S _Read_STDIN_as_character][T   T   T   _Retrieve][S N
S _Duplicate_input][S S S T S S T   N
_Push_9][T  S S T   _Subtract][N
T   S S N
_If_0_Jump_to_Label_PRINT][S N
S _Duplicate_input][S S S T S T S N
_Push_10][T S S T   _Subtract][N
T   S S N
_If_0_Jump_to_Label_PRINT][S N
S _Duplicate_input][S S S T S S S S S N
_Push_32][T S S T   _Subtract][N
T   S S N
_If_0_Jump_to_Label_PRINT][N
S N
N
_Jump_to_Label_LOOP][N
S S S N
_Create_Label_PRINT][T  N
S S _Print_character][N
S N
N
_Jump_to_Label_LOOP]

Huruf S(spasi), T(tab), dan N(baris baru) ditambahkan hanya sebagai penyorotan.
[..._some_action]ditambahkan sebagai penjelasan saja.

Cobalah online (dengan spasi, tab, dan hanya baris baru). Bonus yang bagus adalah saya bisa menggunakan kode ini untuk mengubah kode yang disorot di atas ke program Whitespace mentah (yang saya lakukan dalam TIO ini sebagai contoh), yang biasanya saya gunakan Notepad ++. :)

Penjelasan:

Cukup lurus ke depan. Di sini pseudo-code:

Loop indefinitely:
  Character c = STDIN as character
  if(c == SPACE or c == TAB or c == NEWLINE):
    Print c as character
  Go to the next iteration of the loop
— Kevin Cruijssen
sumber
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