Aneh terkucilkan "Hello World!" [Ditutup]

66

Tugas:

Buat program yang dikaburkan yang mencetak Hello World!(persis seperti itu). Program Anda mungkin tidak memiliki string apa pun di dalamnya.

Aturan:

  • Anda dapat menggunakan bahasa pemrograman apa pun yang Anda suka.
  • Jadikan sesederhana mungkin
  • Ini adalah kontes popularitas , jadi jawaban dengan kemenangan terbanyak menang.

catatan:

Ini bukan duplikat dari pertanyaan ini . Yang itu kode-golf dan punya aturan berbeda.

popularity-contest  obfuscation  hello-world 
— Dokter
sumber
1
Siapa yang pertama mengirim BF? :)
— VisioN
3
@VisioN - Saya akan mempertimbangkan BF tidak benar-benar dikaburkan ...
— TheDoctor
3
dangermouse.net/esoteric/piet/hw1-11.gif adalah program Hello World di Piet. Informasi lebih lanjut: dangermouse.net/esoteric/piet.html
— MatrixFrog
3
"Yang itu kode-golf " tidak membuatnya bukan duplikat . Aturannya memang mengecualikan menyalin jawaban dari pertanyaan yang lebih lama, tetapi terutama karena mereka mengecualikan semua jawaban: tidak ada program yang tidak dapat dikaburkan lebih lanjut.
— Peter Taylor
6
Saya tidak setuju bahwa mereka adalah duplikat, dengan alasan yang berbeda dari sekadar "Yang lain adalah kode-golf". Kode-golf yang mengharuskan subset karakter tertentu tidak pernah digunakan dalam kode sumber, apakah itu dalam string atau tidak. Seharusnya tidak ada pertandingan di salah satu dari mereka entri terhadap regex berikut: /[dehlorw01]/. Juga, panjangnya dinilai. Dalam hal ini, itu tidak memerlukan penggunaan string (dan mungkin tidak char[][], layu). Panjangnya tidak dihitung, tetapi kreativitas adalah faktor penentu utama, dengan demikian tag popularitas-kontes .
— Isiah Meadows

Jawaban:

102

Python 2

Saya kebetulan bermain dengan ini kemarin, jadi:

(lambda _, __, ___, ____, _____, ______, _______, ________: getattr(__import__(True.__class__.__name__[_] + [].__class__.__name__[__]), ().__class__.__eq__.__class__.__name__[:__] + ().__iter__().__class__.__name__[_____:________])(_, (lambda _, __, ___: _(_, __, ___))(lambda _, __, ___: chr(___ % __) + _(_, __, ___ // __) if ___ else (lambda: _).func_code.co_lnotab, _ << ________, (((_____ << ____) + _) << ((___ << _____) - ___)) + (((((___ << __) - _) << ___) + _) << ((_____ << ____) + (_ << _))) + (((_______ << __) - _) << (((((_ << ___) + _)) << ___) + (_ << _))) + (((_______ << ___) + _) << ((_ << ______) + _)) + (((_______ << ____) - _) << ((_______ << ___))) + (((_ << ____) - _) << ((((___ << __) + _) << __) - _)) - (_______ << ((((___ << __) - _) << __) + _)) + (_______ << (((((_ << ___) + _)) << __))) - ((((((_ << ___) + _)) << __) + _) << ((((___ << __) + _) << _))) + (((_______ << __) - _) << (((((_ << ___) + _)) << _))) + (((___ << ___) + _) << ((_____ << _))) + (_____ << ______) + (_ << ___))))(*(lambda _, __, ___: _(_, __, ___))((lambda _, __, ___: [__(___[(lambda: _).func_code.co_nlocals])] + _(_, __, ___[(lambda _: _).func_code.co_nlocals:]) if ___ else []), lambda _: _.func_code.co_argcount, (lambda _: _, lambda _, __: _, lambda _, __, ___: _, lambda _, __, ___, ____: _, lambda _, __, ___, ____, _____: _, lambda _, __, ___, ____, _____, ______: _, lambda _, __, ___, ____, _____, ______, _______: _, lambda _, __, ___, ____, _____, ______, _______, ________: _)))

Ini adalah versi yang lebih mudah dibaca: http://codepad.org/UzSmoxF2

Catatan:

  • Satu baris, ekspresi tunggal (yaitu tidak ada pernyataan cetak).

  • Tanpa string, tanpa int; hanya fungsi, akses atribut, daftar, tupel, matematika dasar, satu True, dan satu argumen bintang.

  • Minimal penggunaan builtin ( __import__, getattr, dan chrsekali masing-masing).

  • Payload dapat diubah dengan mudah. Ini adalah program yang saya tulis untuk membuatnya.

Sunting: Saya menulis penjelasan yang cukup substansial tentang cara kerjanya di blog saya .

— Ben Kurtovic
sumber
7
Bagus. Sangat mudah dibaca.
— devnull
45
"versi yang lebih mudah dibaca"
— ASKASK
2
Selamat atas 100!
— Conor O'Brien
64

JavaScript

([]+/H/)[1&11>>1]+(+[[]+(1-~1<<1)+(~1+1e1)+(1%11)+(1|1>>1|1)+(~1+1e1)+(.1^!1)])[[([]+!![
11])[11^11]+[[{}]+{}][1/1.1&1][1]]+([[]+111/!1][+!1][([{}]+{})[1e1>>1]+[[],[]+{}][1&11>>
1][1|[]]+([]+[][111])[1&1]+[{},1e1,!1+{}][~~(1.1+1.1)][1^1<<1]+(11/!{}+{})[1-~1<<1]+[!!{
}+[]][+(11>11)][[]+1]+(/^/[1.11]+/&/)[.1^!1]+[{},[{}]+{},1][1&11>>1][1+1e1+1]+([]+!!{})[
.1^!1]+([]+{}+[])[[]+1]+[!!{}+{}][!11+!111][[]+1]]+[])[(!/~/+{})[1|1<<1]+[/=/,[]+[][1]][
1&11>>1][1&1>>1]+([]+{})[~~(1.1+1.1)]+[1,!1+{}][1%11][1^1<<1]+(111/[]+/1/)[~1+1e1+~1]+[!
!/-/+[]][+(11>11)][1]]((1<<1^11)+((+(1<1))==([]+/-/[(!![11]+[])[+!1]+(!!/-/+{})[1-~1]+([
]+!/~/)[1-~1]+(!!/-/+{})[!111+!111]])[11%11]),-~11>>1)](~1-~1e1<<1<<1)+([]+{111:1111}+[]
)[11111.1%11.1*111e11|!11]+({}+/W/)[1+~1e1-(~11*1.1<<1)]+(+[[]+(1|1>>1)+(1|1>>1|1)+(11-1
>>1)+(1e1>>1|1)+(1e1>>1)+(1>>11)+(11>>>1)])[[(!!{}+[])[11>>>11]+[[]+{}][.1^!1][111%11]]+
([11/[]+[]][111%111][([{}]+[{}])[1e1>>1]+[[],[{}]+[{}]][1|1>>1|1][1|[]]+([][11]+[])[[]+1
]+[{},1e1,![1]+/~/][1<<!1<<1][1<<1^1]+(1/!1+{})[11+1>>1]+[!!/-/+{}][+(111>111)][111%11]+
([][11]+/&/)[1&1>>1]+[{},[]+{}+[],1][[]+1][11-~1+11>>1]+([]+!!/-/)[11>>11]+([]+{})[1|1>>
1|1]+[[]+!!{}][1>>>1][1&11]]+[])[(!{}+[])[1^1<<1]+[/=/,[]+[][1]][1<<1>>1][!111+!111]+([]
+{}+[])[1<<1^1>>1]+[1,![11]+[]][1|1>>1][1|1<<1|1]+(11/[]+/1/)[-~11>>1]+[!![111]+{}][+[]]
[1|1>>1]]((1e1-1)+((1&1>>1)==([]+/-/[(!!{}+{})[+(1>1)]+(!!/-/+{})[1|1<<1]+(!1+{})[1|1<<1
|1]+(!!/-/+{})[11.11>>11.11]])[1&1>>1]),1-~1<<1)](~1-~1e1<<1<<1)+(/^!/+[])[1+!![11%111]]

Deskripsi cara kerjanya dapat ditemukan dalam jawaban ini di StackOverflow.

Cukup jalankan ini di konsol browser (mis. Di Firebug atau di Chrome Dev Tools).

— Penglihatan
sumber
50

C

Salam berganda:

#include <stdio.h>
main() {
  long long P = 1,
            E = 2,
            T = 5,
            A = 61,
            L = 251,
            N = 3659,
            R = 271173410,
            G = 1479296389,
            x[] = { G * R * E * E * T , P * L * A * N * E * T };
  puts((char*)x);
}
— osifrque melengking
sumber
Anda tidak dapat memiliki STRING!
— Mukul Kumar
19
Saya tidak berpikir dia menggunakan tali. Dia hanya mengetikkannya.
— microbian
3
Ini pintar - dan bahkan tidak melibatkan perilaku yang tidak terdefinisi, meskipun penampilan (lebih baik Anda harus menggunakan 'lama tidak ditandatangani') - tetapi hanya bekerja pada sistem little-endian.
— zwol
50

PHP

<?=${[${[${[${[${[${[${[${[${${![]}.=[]}.=${![]}{!![]}]}.=${!![${[${[
${[${[${[${[${[]}++]}++]}++]}++]}++]}++]}++]}{![]+![]+![]}]}.=${[${[$
{[${[${[]}++]}++]}++]}++]}{![]}]}.=${[${[${[${[${[${[${[${[]}++]}++]}
++]}++]}++]}++]}++]}{![]+![]}.${[]}{![]+![]}]}.=${![]}^${!![${[${[${[
]}++]}++]}++]}{![]+![]+![]}]}.=${[]}{!![]}]}.=${[${[${[${[${[${[${[${
[${[${[${[${[${[${[${[${[]}++]}++]}++]}++]}++]}++]}++]}++]}++]}++]}++
]}++]}++]}++]}++]}{![]+![]+![]+![]}.${[]}{![]+![]+![]+![]}]}.=${[${[$
{[${[]}++]}++]}++]}{![]+![]}.${![]}{![]+![]+![]}]}.=${[${![]}=${![]}{
!![]}]}{!![${!![${!![${![]}++]}++]}++]}^${!![${[${[${[]}++]}++]}++]};

Saya telah menerjemahkan ini ke dalam satu pernyataan, yang menurut saya membuatnya lebih sulit untuk diuraikan. Versi ini hanya menggunakan 13 karakter unik.

Versi asli

<?${[]}.=[];${![]}.=${[]}{!![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${
![]};++${![]};${![]}.=${[]}{![]+![]+![]};++${![]};++${![]};++${![]};++${![]};${![
]}.=${![]}{![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]};${
![]}.=${![]}{![]+![]}.${![]}{![]+![]};++${![]};++${![]};++${![]};${![]}.=${[]}^${
[]}{![]+![]+![]};${![]}.=${![]}{!![]};++${![]};++${![]};++${![]};++${![]};++${![]
};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]};++${![]
};++${![]};${![]}.=${![]}{![]+![]+![]+![]}.${![]}{![]+![]+![]+![]};++${![]};++${!
[]};++${![]};${![]}.=${![]}{![]+![]}.${[]}{![]+![]+![]};++${![]};++${![]};++${![]
};${[]}=${[]}{!![]};++${[]};++${[]};++${[]};${![]}.=${[]}^${![]}{![]}?><?=${![]};

14 karakter unik. Saya bisa membuat skrip untuk menghasilkan ini dan menyebutnya "PHPFuck", tapi saya pikir itu tidak akan sangat berguna.

Bagaimana itu bekerja

Ketika sebuah array - termasuk array kosong - dilemparkan ke string, hasilnya selalu string "Array" yang luar biasa membantu. Saya tidak yakin siapa yang berpikir itu ide yang bagus. PHP mendukung operator kenaikan (tetapi bukan penurunan) untuk string, misalnya "++ A" → "B". String asli berisi "A" dan "a", sehingga semua karakter latin dapat diproduksi dengan gaya brainfuck. Ruang diproduksi dengan "A" ^ "a", dan seru dengan "D" ^ "e".

— primo
sumber
Saya sangat ingin tahu tentang bagaimana cara membuat skrip untuk menghasilkan jenis kebingungan ini, jika Anda memiliki 5 menit untuk membahasnya, saya akan sangat menghargai itu =] Saya akan berada di chat.stackexchange.com/rooms/13342/weirdest -obfuscations
— Jeffrey L. Roberts
Saya baru saja melihat sumber jsfuck, menarik ... Saya mengharapkan sesuatu yang sedikit lebih dinamis daripada peta char =] ... Saya akan bersantai di ruangan itu jika ada yang ingin bergabung =]
— Jeffrey L. Roberts
2
Ini jauh lebih baik daripada jawaban Javascript, yang memiliki /H/dan /W/di dalamnya.
— durron597
39

PHP

Berikut ini skrip PHP sederhana yang ditampilkan Hello World!:

<?php
function SGVsbG8gV29ybGQh($_ = 0) {(
    $___=__FUNCTION__
    )&&
    !$_ and list($_,$__) = array_values(array_filter($___(42), $___)) and
    !$_($__($___)) and
    $___($___); return
    $_
    &42
    ?current(get_defined_functions()):(
    !((
    $_=md5($_))-42*2)or
    !(md5($_ = md5($_))-42/2
    *3)
);};

SGVsbG8gV29ybGQh();

Klik di sini untuk demo.

— Razvan
sumber
11
Saya masih tidak tahu mengapa itu mencetak apa pun.
— Primo
1
@primo Nama fungsi adalah kuncinya;)
— VisioN
Decoding Base64?
— Linuxios
Itu juga, tapi sedikit lebih.
— Razvan
1
@ Razvan Sudahkah Anda mencoba semua fungsi bawaan periksa jika hanya dua hash yang dimulai dengan 84 dan 63? Itu brilian!
— VisioN
34

Ruang putih

   	  	   
	
     		  	 	
	
     		 		  
	
     		 		  
	
     		 				
	
     	     
	
     	 	 			
	
     		 				
	
     			  	 
	
     		 		  
	
     		  	  
	
     	    	
	
  

Wikipedia: Whitespace (bahasa pemrograman) Juru Bahasa
Online untuk Menguji Jawaban

Program mendorong kode karakter ASCII melalui langkah-langkah berikut (diambil dari bilah sisi debug penerjemah):

tekan 72
printc
tekan 101
printc
tekan 108
printc
tekan 108
printc
tekan 111
printc
tekan 32
printc
tekan 87
printc
tekan 111
printc
tekan 114
printc
tekan 108
printc
tekan 100
printc
tekan 33
printc
akhir
— grovesNL
sumber
8
Untuk poin tambahan, kombinasikan ini dengan yang bukan spasi juga.
— zebediah49
33

Bash (di Linux)

Saya harap skrip shell Anda tidak terlihat seperti ini:

:; ______=$? __=${#______} ____=$[__+__] ________=$[__+____] _____=$[____+____]
     __________=$[____+_____] _________=$[__+__________] ______________=(
            /????/$$/????) ____________=${______________[$______]} 
   _____________=${____________##*/} _______________=(${____________//\// })
          ________________=${_______________: -$__:$__}$_____________
           ___________________=${________________:$______:$________}
   ___________=${_____________:$______:$__} _________________=${___________^}
     . <($___________________<<<__________________=\({$_________________..\
${___________}}\))&&_______=(${__________________[@]:$______:$____$__________})
  ___=(${_______[@],,})&&${___[$_____]}${___[$____]}${___[$_________]}${___[
$__$_____]} -${___[$_____]} ${_______[ $_________]}${___[${_____}]}${___[$__$__
]}${___[$__$__]}${___[$__$_____]} ${_______[$____$____]}${___[$__$_____]}${___[
$__$_________]}${___[ $__$__]}${___[$________]}\\$______$[$_____#$____$____$__]
  • Bukan karakter alfanumerik tunggal - mengingat pembatasan ini, sepertinya tidak ada gunanya melakukan kebingungan lebih lanjut
  • Tanpa string (tidak ada kutipan, pokoknya)
  • Ada ketergantungan pada Linux - khususnya bahwa attrfile tersebut adalah file pertama /proc/$PIDdengan nama file 4 karakter

Lihat apakah Anda dapat menemukan yang tersembunyi eval.

— Trauma Digital
sumber
Tampaknya ada beberapa batasan pada rendering SO: Saya mengatakan bahwa baris terakhir dapat dimulai dengan ${__[${____}]}${__[${__________}]}${__[${_______}]}${__[${___}${____}]} -${__[${____}]} ( echo -e) dan digantikan ! oleh\\${_________}${____}${___}
— F. Hauri
atau terburuk: \\${_________}$[${______}${____}#${_____[${___________}+${__________}]}]buatlah tanda seru juga ;-)
— F. Hauri
Ini cantik . Tetapi ada beberapa masalah: (1) itu tidak terlalu portabel, saya tidak bisa menjalankannya seperti pada BSD. (2) skrip mengasumsikan bahwa _________akan diatur ke 0(apa yang akan terjadi jika skrip sourced bukan setelah kesalahan?).
— devnull
@devnull 2) mudah diperbaiki - cukup jalankan :perintah untuk menghapus semua kondisi kesalahan yang dilaporkan sebelumnya $?.
— Digital Trauma
3
@devnull Maaf, tidak ada hadiah, selain rasa puas diri ;-)
— Digital Trauma
29

GolfScript

[' '(..4/++][' '(3*)))))][6`(2*.]['1'..++~][8 2?2/][' '(4/.(`\`\+~]['1'.+~2?10-][13(1)?8((0)))))*-][6`(1)*]['('(4/2?][' '()]+++++++++++

Cukup menantang untuk membuat dan men-debug ini. Itu tidak mengandung string, hanya karakter.

Ini menghasilkan:

Halo Dunia!

Tes online

Penjelasan

Bagaimana ini bekerja:

  1. [' '(..4/++]
    1. ' '(mengubah ruang untuk kode ASCII-nya: 32.
    2. ..duplikat 32dua kali. Sekarang kamu punya tiga kali 32.
    3. 4/membagi atas 32dengan 4. Sekarang Anda memiliki dua kali 32dan satu kali 8.
    4. ++menambahkan 32, 32dan 8. Anda dapatkan 72, yang merupakan kode ASCII untuk H.
  2. [' '(3*)))))]
    1. ' '(mengubah ruang menjadi 32.
    2. 3*gandakan 32dengan 3:96
    3. )))))meningkat 96dengan 5, Anda dapatkan 101, yang merupakan kode ASCII untuk e.
  3. [6`(2*.]
    1. 6`(memberikan kode ASCII dari char 6:54
    2. 2*kalikan dengan 2, Anda dapatkan 108, yang merupakan kode ASCII untuk l.
    3. . duplikat l
  4. ['1'..++~]
    1. '1'..menempatkan char 1di stack dan menduplikatnya dua kali.
    2. ++ menggabungkan tiga karakter dan mengembalikan string 111
    3. ~mengubahnya menjadi integer 111, yang merupakan kode ASCII untuko
  5. [8 2?2/]
    1. 8 2?menghitung 8 2 , Anda dapatkan64
    2. 2/membaginya dengan 2, Anda dapatkan 32, yang merupakan kode ASCII untuk spasi.
  6. [' '(4/.(`\`\+~]
    1. ' '(mengubah ruang menjadi 32.
    2. 4/.membaginya dengan 4, Anda dapatkan 8. The .duplikat itu.
    3. (`decrements yang kedua 8dan mengubahnya menjadi string.
    4. \menukar dua elemen teratas. Itu 8menjadi elemen teratas.
    5. `mengkonversi 8ke string.
    6. \menukar dua elemen teratas. Itu 7menjadi elemen teratas.
    7. +menggabungkan dua string. Anda mendapatkan 87(sebagai string).
    8. ~mengkonversi string 87ke integer 87, yang merupakan kode ASCII untuk W.
  7. ['1'.+~2?10-]
    1. '1'.menempatkan char 1di stack dan menduplikatnya.
    2. +~menggabungkan dua karakter ke string 11dan mengubahnya menjadi integer.
    3. 2?menghitung 11 2 , Anda dapatkan 121.
    4. 10-menurun 121dengan 10, Anda mendapatkan kode ASCII untuk o: 111.
  8. [13(1)?8((0)))))*-]
    1. 13(menempatkan 12di tumpukan.
    2. 1)menempatkan 2di tumpukan.
    3. ?menghitung 12 2 , Anda dapatkan 144.
    4. 8((menempatkan 6di tumpukan.
    5. 0)))))menempatkan 5di tumpukan.
    6. *mengalikan 6dan 5, Anda dapatkan 30.
    7. -kurangi 144dengan 30, Anda dapatkan 114, yang merupakan kode ASCII untukr
  9. [6`(1)*]
    1. 6`(dikonversi 6menjadi char dan ambil kode ASCII-nya:54
    2. 1)*mengalikan 54dengan 2, Anda dapatkan 108, kode ASCII daril
  10. ['('(4/2?]
    1. '('(dikonversi (ke kode ASCII-nya 40,.
    2. 4/dibagi 40dengan 4, Anda dapatkan 10.
    3. 2?menghitung 10 2 , Anda dapatkan 100, yang merupakan kode ASCII untukd
  11. [' '()]
    1. ' '( mengubah spasi menjadi kode ASCII-nya: 32
    2. )menambah 32, Anda dapatkan 33, yang merupakan kode ASCII untuk!
  12. +++++++++++ menggabungkan semua kode ASCII menjadi satu string.
— ProgramFOX
sumber
11
+1 untuk penjelasan yang bagus. Ini tidak biasa untuk jawaban skrip golf karena beberapa alasan.
— Digital Trauma
@DigitalTrauma Saya cukup yakin ada alasan yang bagus
— qwr
2
Ini adalah pertama kalinya saya melihat jawaban GolfScript panjang untuk masalah yang biasanya diselesaikan dengan sepele.
— Victor Stafusa
20

Brainf ***

Tidak yakin apakah ini benar-benar dianggap membingungkan, tetapi tidak pernah menggunakan lebih dari empat simbol plus atau minus berturut-turut. Jadi begitulah.

>>+++[<+++>-]<+[>+++>>+++[<+++>-]<+[<]>-]<+++[>+++<-]>+[>++++<-]>++.>+.>+++
[<++>-]<+..+++.<<<+++[>+++<-]>+[>----<-]>.>[>+>+<<-]++++[>++<-]>.>.+++.>++[
<--->-]<.>++[<---->-]<.<<<+.
— Jwosty
sumber
14
+1 untuk mengatakan apa pun yang mungkin tidak dihitung Brainfuck sebagai dikaburkan.
— RubberDuck
Sementara itu, pada tahun 1992 ... "Setiap program dapat dikaburkan! Dan ketika setiap program dikaburkan ..." <Urban Müller terkekeh jahat> " tidak ada program yang akan ..."
— Code Jockey
19

Mathematica

Matematika Aljabar I sederhana.

a=+x+8x^2+8(x^3+x^9);
b=11(x^4+x^7)-68x^5-13x^6;
c=-28+14x^8-67x^11;
w=ToExpression[Names[__][[1571]]];  
v=ToExpression[Names[__][[604]]]; 
y=Solve[a+b+c,{x},Reals];  
w[v[y[[1]],x]+100]

Halo Dunia!

— DavidC
sumber
2
FromCharacterCodeistirahat semua intrik ...
— VisioN
1
VisionN, FromCharacterCodesekarang dikaburkan. Begitu juga CoefficientList.
— DavidC
17

C

#define u unsigned char
#define v while(*x)
#define z(x) putchar(*x);
#define y(x) ++*x;
#define p(x) ++x;
#define e(x) --*x;
#define d(x) --x;
#define w(x) x x
main(){u *x=calloc(12,1);u *l=x;w(w(w(y(x))))w(y(x))v{p(x)w(w(y(x)))w(y(x))y(x)p
(x)w(w(w(y(x))))w(y(x))p(x)w(y(x))y(x)p(x)w(w(w(y(x))))y(x)w(w(d(x)))e(x)}p(x)w(
y(x))z(x)p(x)y(x)z(x)w(w(y(x)))w(y(x))y(x)w(z(x))w(y(x))y(x)z(x)p(x)w(y(x))z(x)p
(x)w(e(x))e(x)z(x)w(d(x))z(x)w(y(x))y(x)z(x)w(w(e(x)))w(e(x))z(x)w(w(w(e(x))))z(
x)p(x)y(x)z(x)free(l);}

Meta-dikaburkan. Menjalankan ini melalui preprocessor memberi Anda ini:

main(){unsigned char *x=calloc(12,1);unsigned char *l=x;++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x;++*x; ++*x;while(*x){++x;++*x; ++*x; ++*x; ++*x;++*x; ++*x;++*x;++x;
   ++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x;++*x; ++*x;++x;++*x; ++*x;++*x;++x;++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x; ++*x;++*x;--x; --x; --x; --x;--*x;}++x;++*x; ++*x;
     putchar(*x);++x;++*x;putchar(*x);++*x; ++*x; ++*x; ++*x;++*x; ++*x;++*x;putchar(*x); putchar(*x);++*x; ++*x;++*x;putchar(*x);++x;++*x; ++*x;putchar(*x);++x;
   --*x; --*x;--*x;putchar(*x);--x; --x;putchar(*x);++*x; ++*x;++*x;putchar(*x);--*x; --*x; --*x; --*x;--*x; --*x;putchar(*x);--*x; --*x; --*x; --*x; --*x; --*x; --*x; --*x;putchar(*x);
  ++x;++*x;putchar(*x);free(l);}

Keluaran:

Halo Dunia!

Sunting: menambahkan penyorotan sintaks untuk kejelasan. :-P

— Komintern
sumber
3
Bagus. Belum pernah melihat logika BF digunakan di C sebelumnya.
— Isiah Meadows
@OP Menghapus u *l=x;dan free(l);memberi saya hasil yang sama.
— Lucas Henrique
@IsiahMeadows Apa itu logika BF?
— YoTengoUnLCD
@YoTengoUnLCD Brainfuck
— Isiah Meadows
15

Sage

for i in 5105882569598991528047304.digits(1+sum(2**j for j in 11382954456.digits(42))):
    sys.stdout.write(chr(i))

Penjelasan:

11382954456.digits(42) mengkonversi 11382954456 menjadi basis 42 dan memberikan array dari digit-nya, yaitu [6, 1, 0, 5, 4, 3, 2]

Jadi sumsebenarnya memberikan jumlah 1 + 2 + 4 + ... + 32 + 64, yaitu 127

Kemudian 5105882569598991528047304.digits(...)mengonversi angka menjadi basis 128, yang memberikan daftar[72, 101, 108, 108, 111, 32, 87, 111, 114, 108, 100, 33]

Dan ini adalah kode ASCII untuk string yang akan dicetak.

— ace_HongKongIndependence
sumber
3
Belum pernah mendengar orang bijak sebelumnya
— TheDoctor
@TheDoctor diedit untuk menambahkan hyperlink ke halaman web Sage.
— ace_HongKongIndependence
Ini mirip sekali dengan python
— TheDoctor
@TheDoctor karena Sage didasarkan pada python
— ace_HongKongIndependence
15

Javascript (28187 karakter)

Mungkin bukan cara terpendek untuk menyapa dunia ini. 

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Dihasilkan dengan JSFuck

— Michael M.
sumber
3
+1 Saya juga ingin mengirim jawaban JSFuck, tetapi Anda melakukannya terlebih dahulu.
— Victor Stafusa
5
Mungkin Anda harus menyebutkan bahwa Anda telah membuat kode ini dengan JSFuck .
— VisioN
3
Gandakan codegolf.stackexchange.com/q/17950/3103 . Dan ya, ada cara yang lebih pendek untuk melakukannya.
— Konrad Borowski
12

C:

#include <stdio.h>
#define BING(x,y) ((x)<<y)
#define BANG(x)   (1<<x)
#define BOOM      1
int main () {
  int x,y,z,w;
  int V[3] = {BING(x=227380393,BANG(BOOM)+BOOM), x+(w=BOOM+BANG(BANG(BOOM)),
              BING(47*y=17453197,BOOM)), x+y+BING(w*w*17*185527,BANG(BOOM))};
  char *p=V;
  while(*(p-BOOM)!=BOOM+BING(BOOM,w)) putchar(*p++);
  return 0;
} /* Mind the comma operator! */

Output:

Hello World!

— recursion.ninja
sumber
Array integer dengan sedikit perubahan ... dimainkan dengan baik. Saya juga suka yang terakhir bergeser ke kanan dalam jumlah yang cukup besar.
— Isiah Meadows
12

Malbolge

('&%:9]!~}|z2Vxwv-,POqponl$Hjig%eB@@>}=<M:9wv6WsU2T|nm-,jcL(I&%$#"
`CB]V?Tx<uVtT`Rpo3NlF.Jh++FdbCBA@?]!~|4XzyTT43Qsqq(Lnmkj"Fhg${z@>

atau

(=<`#9]~6ZY32Vx/4Rs+0No-&Jk)"Fh}|Bcy?`=*z]Kw%oG4UUS0/@-ejc(:'8dc

Saya tidak tahu bagaimana ini bekerja.

Sumber: http://en.wikipedia.org/wiki/Malbolge#.22Hello_World.21.22_in_Malbolge

— The Guy with The Hat
sumber
8
Aku cukup yakin bahwa seluruh titik dari Malbolge adalah bahwa tidak ada yang memiliki petunjuk bagaimana itu bekerja.
— Edmund Schweppe
@ EdmundSchweppe Ya, tapi tidak semua orang tahu itu.
— The Guy with The Hat
Anda mengalahkan saya dengan yang ini (+1).
— arshajii
1
Namun seseorang, entah bagaimana, menyelesaikan tantangan 99 Botol menggunakan Malbolge: 99-bottles-of-beer.net/language-malbolge-995.html Bahkan, orang lain juga melakukannya: 99-bottles-of-beer.net /language-malbolge-375.html
— KBKarma
11

Jawa

Ini dia. Bisakah Anda mengerti cara kerjanya?

Peringatan: Sangat fluktuatif. Dapat pecah secara spontan di masa depan.

import java.io.ByteArrayOutputStream;

public class MysteryCode {
    public static void main(String[] unused) throws Exception {
        ByteArrayOutputStream stoned = new ByteArrayOutputStream(20480);
        int[] magic = {104, 116, 116, 112, 58, 47, 47, 98, 105, 116, 46, 108, 121, 47, 49, 98, 87, 119, 51, 75, 111};
        for (int weird : magic) stoned.write(weird);
        int crazy, unknown = 0;
        java.io.InputStream wtf = new java.net.URL(stoned.toString()).openStream();
        while((crazy = wtf.read()) != -1) stoned.write(crazy);
        for (int strange : stoned.toByteArray()) {
            if (unknown == 2) {
                if (strange == 38) break;
                System.out.print((char) strange);
            } else if (17 + (unknown + 1) * 21 == strange) {
                unknown++;
            }
        }
    }
}
— Victor Stafusa
sumber
1
Menarik Anda membuat parser untuk halaman ini. Dilakukan dengan sangat baik
— Cruncher
4
Saya kira Anda tidak akan keberatan jika seseorang mengubah judul untuk pertanyaan ini? ;)
— Cruncher
2
@Cruncher Saya pikir judul pertanyaannya sempurna dan sama sekali tidak melihat alasan untuk mengubahnya. ;)
— Victor Stafusa
5
Menariknya menggunakan nama variabel seperti gila, tidak dikenal dan aneh lebih sulit dibaca daripada menggunakan x, y, z. Sangat mudah untuk membedakan antara x's, y's, dan z's, tetapi sinonim (psuedo-) dapat membuat Anda marah.
— Cruncher
4
while((crazy = wtf.read()) != -1) stoned.write(crazy);xD
— Cruncher
10

Dibalik

Kode yang mengatakan "Halo, Dunia!":

>55+7*2+,  v >4*4+v
              ,
v,+1*+55+55< +v55<>55+3*2+,v
>55+55+*8+,v 5+  +v,+7*8+55<
v,+8*+55+55< 5*  5>55+55+*56++,v
>55+55+*56++,^8  5v,++59*+55+55<
v+55,*+55+55,+<  ^<
>3*3+,@

Kode yang bertuliskan "Hello World!":

>55+7*2+,  v >    v

v,+1*+55+55<  v55<>55+3*2+,v
>55+55+*8+,v  +  +v,+7*8+55<
v,+8*+55+55<  *  5>55+55+*56++,v
>55+55+*56++,^8  5v,++59*+55+55<
v+55,*+55+55,+<  ^<
>3*3+,@
— Misteriggy
sumber
Umm, pada awalnya tertulis "Hello, World" (dengan koma), dan yang baru mengatakan "Hello World" tanpa koma.
— Misteriggy
Dan sekarang saya sudah menginstalnya kembali.
— Misteriggy
Oh Revisi 2 lebih masuk akal sekarang. Saya hanya melihat Revisi 1 saat mengedit (tidak tahu mengapa). Maaf atas kebingungan
— John Dvorak
Tidak masalah ... Senang masuk akal sekarang :).
— Misteriggy
10

Jalak 98 - 7610 karakter

'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,  '/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+'/'[\/+,@

Berdasarkan jawaban saya di sini: https://codegolf.stackexchange.com/a/15736/9498

Sebagai bonus, jawaban ini tidak menggunakan angka apa pun dan tidak mengandung karakter yang berlebihan (yaitu tidak ada kombinasi karakter yang dapat dihapus sehingga menghasilkan output yang sama).

Cobalah di sini (rekatkan kode, ganti setiap instance '/'[dengan "/["): http://www.quirkster.com/iano/js/befunge.html

Bagaimana itu bekerja:

'/'[\/ setara dengan 1, jadi semua yang dilakukan adalah kenaikan nilai ASCII yang sesuai, lalu dicetak.

Bonus tambahan: posting ini sangat panjang sehingga dibutuhkan ~ 1 detik sebelum stackexchange mengakui perubahan dalam penulisan posting ini.

— Justin
sumber
Anda masih menggunakan string ... Bahkan "/ [" adalah sebuah string.
— Misteriggy
@Misteriggy Whoops melewatkan persyaratan itu. Memperbaiki ...
— Justin
@Misteriggy Ada. Sekarang tidak menggunakan string.
— Justin
10

Brainf ** k

Ini dikaburkan, namun, itu tidak bisa lebih sederhana.

+   +  +++++  +      [         >++
+   +  [      >      +        +   >
+++>+  ++>+<  <      <        <   -       
]   >  +      >      +        >   -    >
>   +  >+[<]  <-]>>  .>---     .++    +

+   +   ++.   .+++   .        >>.<     -
W . <  .   +  +   +  .        -   -    -
- - -  .   -  ----   -        -   -    .
 > >   +   .  > +    +        .   <
        >>>   <  <   >>><<    <><>     >

Karena ketika Anda melihat dari dekat:

H   H  EEEEE  L      L         OOO
H   H  E      L      L        O   O
HHHHH  EEEEE  L      L        O   O       
H   H  E      L      L        O   O     ,
H   H  EEEEE  LLLLL  LLLLL     OOO     ,

W   W   OOO   RRRR   L        DDDD     !
W W W  O   O  R   R  L        D   D    !
W W W  O   O  RRRR   L        D   D    !
 W W   O   O  R R    L        D   D
        OOO   R  R   LLLLL    DDDD     !
— ASCIIThenANSI
sumber
7

JavaScript

Tidak ada angka literal, tidak ada string literal, dan hanya satu fungsi (tidak termasuk console.log)!

var ________________ = [] + []; var _ = +[]; _++; var _____ = _ + _;
var ___ = _____ + _____; var __ = ___ + ___; var ____ = __ + __; var ______ = ____ + ____;
var _______ = ______ + _; var ___________ = ______ + ______ + __;
var ______________ = ___________ + ____ -  _; var ____________ = _ + _____;
var ________ = _______ * ____________ + _; var _________ = ________ + _;
var _____________ = ______________ + ______ - ___ - _; var __________ = _____________ -
____________; var _______________ = __________ - ____________; console.log(________________ +
String.fromCharCode(___________, _________, _______________, _______________, __________,
______, ______________, __________, _____________, _______________, ________, _______));

Demonstrasi di sini .

— The Guy with The Hat
sumber
Tapi bukankah []literal?
— Ismael Miguel
@ IsmaelMiguel Itu mungkin benar, tapi itu bukan angka atau string literal.
— The Guy with The Hat
1
Maaf, saya salah membaca apa yang Anda katakan. Anda bilang No number literals, dan saya melewatkan nomornya. Jika mau, bisa digunakan Array()sebagai gantinya. Itu tidak akan menjadi literal. Dan itu akan membuatnya lebih membingungkan. Atau, Anda dapat menggunakan +falseuntuk +[]. Atau bahkan Array()-Array().
— Ismael Miguel
7

Python 2.6+

p = lambda x: ( -13214 * x**11 + 956318 * x**10 - 30516585 * x**9 + 564961485 * x**8
                - 6717043212 * x**7 + 53614486464 * x**6 - 291627605005 * x**5
                + 1074222731065 * x**4 - 2606048429424 * x**3 + 3927289106268 * x**2
                - 3265905357360 * x + 1116073728000 ) / 19958400

print bytearray(map(p, range(1, 13)))

Tidak ada string, hanya fungsi polinomial sederhana .

— Ilmari Karonen
sumber
6

Bahasa Pemrograman ini

            'Alice'++++7/4+v
v     -9/3++'was'          <
>           'beginning'++++++++9/3+v
v      -5/2+'to'                   <
>           'get'++3/5+v
v  -&81/9+++'very'     <
>           'tired'++++6/2-v
v      +5/2+'of'           <
>           'sitting'++++++7/4+v
v      -1/2+'by'               <
>           'her'++3/6-v
v-&14/9+++++'sister'   <
>           'on'~~v
v        ~~~'the' <
>           'bank.'~~~~~s;

Bisakah Anda menebak apa fungsinya?
Mungkin Anda harus masuk lebih dalam ke dalam lubang kelinci untuk mengetahuinya.

PENOLAKAN: Bahasa pemrograman lebih baru daripada tantangan.

— BobTheAwesome
sumber
Itu adalah penafian yang layak.
— Kzqai
Penerjemahnya dihancurkan oleh spesifikasi Khan Academy yang baru, saya harus mencari cara untuk memperbaikinya; Saya pikir saya bisa melewati spesifikasi dengan menanamkan dalam halaman HTML.
— BobTheAwesome
5

C

int main() {
    // Some floating point numbers for testing
    float b[] = {1.1431391224375825e+27, 6.6578486920496456e+28, 7.7392930965627798e-19, 3.2512161851627752e-9};
    // Print all numbers in array b[]
    puts(b);

    return 0;
}

Komentar ada hanya untuk menyesatkan pembaca yang tidak informasi.

Konstanta dikonstruksi sedemikian sehingga perwakilannya dalam memori (untuk sistem little-endian) sama dengan string "Hello World!". Kemudian array (decay to pointer) dilewatkan ke puts, di mana putsmembabi buta memperlakukannya sebagai a char*dan mencetak semuanya sampai hits NUL(yang dikodekan dalam angka terakhir).

Kode mengkompilasi (dengan peringatan) dan mencetak output yang diharapkan dengan gcc 4.7.0, Windows 7 32-bit.

— n̴̖̋h̷͉̃a̷̭̿h̸̡̅ẗ̵̨́d̷̰̀ĥ̷̳
sumber
5

Jawa

class M‮{public static void main(String[]a‭){System.out.print(new char[]{'H','e','l','l','o',' ','W','o','r','l','d','!'});}}

Tes di sini.

Saya tahu, agak lumpuh untuk menggunakan karakter, bukan string. Aneh bahwa itu berjalan dengan benar. Bukan?

— TheNumberOne
sumber
2
Tunggu apa?! Apa mekanisme di balik yang ini?
— Matthew Sainsbury
2
Ada karakter " RIGHT-TO-LEFT OVERRIDE " unicode tepat setelah M, dan sebaliknya (kiri ke kanan) tepat sebelum a[].
— Steve Bennett
3

C (jujur, preprocessor 90% C):

#if __COUNTER__ == 0
#define Y
#define X(a) a##ng a##ng
#define values(a,b,c,d) _ d c = b 5237610348992605899, -8965656808041882953, -3202399561689361469, -7073034487879198273, -7020069900579512688, -33906882022564967 a
#define W(a) (){
#define _Q(a,b,c,d,e) e##a##d##e##c 0; b
#define Q(a,b,c,d) _Q(a,b,c,d,r)
#define K (char
main W(lo) X(lo) values(},{,],[);
#endif
#ifndef T
#undef W
#define W _-
#define Z 35
#define T Y+0
#endif
putchar((*_=(X(lo))(K*)(_+((*W 1)&-(*W 0)|!T))+__COUNTER__),~*K*)(*W 1)));
#if __COUNTER__ <= Z
#include "main.c"
#else
Q(e,},n,tu)
#endif

Hanya dengan gcc atau kompiler lain yang mendukung __COUNTER__makro.

— ApproachingDarknessFish
sumber
3

(Aku tahu itu tidak terlalu aneh .)

dc

dc<<<"8 9*P101P108P108P111P4 8*P81 6+P111P114P108P100P33P"

Keluaran:

Hello World!
— devnull
sumber
1
Saya mendapatkan "Hello World! $" Dengan $ adalah prompt saya. Tambahkan 10P di akhir untuk mendapatkan baris baru.
— Glenn Randers-Pehrson
sebagai alternatifdc<<<5735816763073005734600101863690P
— Digital Trauma
3

C #

Tidak ada string atau karakter literal, meskipun fungsi string yang digunakan. Kebingungan melalui rot13.

using System;
using System.IO;

namespace CodeGolf
{
    /// <summary>
    /// Jevgrf "Uryyb Jbeyq!" gb gur pbafbyr.
    /// </summary>
    /// <remarks>
    /// <para>Guvf cebtenz vf n cebcbfrq fbyhgvba gb dhrfgvba 
    /// ahzore 22533 ng pbqrtbys.fgnpxrkpunatr.pbz:</para>
    /// <para>Perngr na boshfpngrq cebtenz gung cevagf Uryyb 
    /// Jbeyq! (rknpgyl yvxr gung). Lbhe cebtenz znl abg unir 
    /// nal fgevatf va vg.</para>
    /// <para>Fnyhgba Zbaqb vf Rfcrenagb sbe Uryyb Jbeyq.</para>
    /// </remarks>
    class FnyhgbaZbaqb
    {
        class Genafyngbe
        {
            int bssfrg = 0;
            public char Genafyngr(string vachg)
            {
                return vachg.Length < 6
                    ? (char)(37 + (bssfrg -= bssfrg) - vachg.Length)
                    : vachg.ToCharArray()[bssfrg++];
            }
        }
        enum UryybJbeyq
        {
            Hoover,
            Denver,
            WillowPrimus,
            WillowSecundus,
            WillowTertius,
            Fnord,
            Wintergreen,
            Copacetic,
            Pursuing,
            Follicle,
            Remedies,
            Bang
        }
        void Terrg(TextWriter tw)
        {
            Genafyngbe gf = new Genafyngbe();
            foreach (var enumVal in Enum.GetNames(typeof(UryybJbeyq)))
            {
                tw.Write(gf.Genafyngr(enumVal));
            }
            tw.WriteLine();
            tw.Flush();
        }
        static void Main(string[] args)
        {
            FnyhgbaZbaqb urryb = new FnyhgbaZbaqb();
            urryb.Terrg(Console.Out);
            Console.ReadLine();
        }
    }
}
— Edmund Schweppe
sumber
bagaimana bit ke-33 dari integer 4byte bisa bekerja ...
— masterX244
@ masterX244 dengan cukup baik, terima kasih :-)
— Edmund Schweppe
@ masterX244 Sebuah petunjuk: ia mengulangi nama-nama UryybJbeyqenum dan menambah indeks surat mana yang akan diambil dari nama atau mengatur ulang indeks, berdasarkan pada berapa lama nama itu.
— Edmund Schweppe
bagus :) sekarang saya melihat
— masterX244
3

C

#include <stdio.h>
#define o stdout
#define p fputs
int main(_){int*I=&_,_I=2113,l1=3271;_=14557;_I*=503;_<<=3;_*='=';_I<<=0==0;_I=7*'Y'*853<<2;
p(I,o);I=&_I;p(I,o);I=&_;

    _+= l1*11*11;

_I += 0xF5<<8;p(I,o);I=&_I;p(I,o);}

Tanpa string, tanpa array, tanpa karakter, sangat sedikit "konstanta besar penyimpan data" yang jelas.

— vsz
sumber
3

C ++

#include<iostream>
int main()
{
    char    g=16777288,
            r=16777317,
            e=16777324,
            t=16777327,
           sp=16777248,
            w=16777303,
            o=16777327,
            R=16777330,
            l=16777324,
            d=16777316,
           ex=16777249;
    std::cout
            <<g
            <<r
            <<e
            <<e
            <<t
                <<sp//space
                    <<w
                    <<o
                    <<R
                    <<l
                    <<d
                        <<ex;//exclamatory
    return 0;
}

Keluaran

Hello World!
— Mukul Kumar
sumber
1
Saya akan lebih cenderung untuk mendukung Anda jika Anda menghilangkan konstanta o dan l. Anda tidak membutuhkannya, gunakan r dan t sebagai gantinya.
— Level River St
2
@steveverrill yang tidak akan membuat presentasi yang saya inginkan ... 'menyapa dunia' masih akan saya coba
— Mukul Kumar
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