C # HttpClient 4.5 multipart / unggah formulir data

Adakah yang tahu cara menggunakan HttpClientin .Net 4.5 dengan multipart/form-datamengunggah?

Saya tidak dapat menemukan contoh di internet.

hasil saya terlihat seperti ini:

public static async Task<string> Upload(byte[] image)
{
     using (var client = new HttpClient())
     {
         using (var content =
             new MultipartFormDataContent("Upload----" + DateTime.Now.ToString(CultureInfo.InvariantCulture)))
         {
             content.Add(new StreamContent(new MemoryStream(image)), "bilddatei", "upload.jpg");

              using (
                 var message =
                     await client.PostAsync("http://www.directupload.net/index.php?mode=upload", content))
              {
                  var input = await message.Content.ReadAsStringAsync();

                  return !string.IsNullOrWhiteSpace(input) ? Regex.Match(input, @"http://\w*\.directupload\.net/images/\d*/\w*\.[a-z]{3}").Value : null;
              }
          }
     }
}

Ini berfungsi kurang lebih seperti ini (misalnya menggunakan file gambar / jpg):

async public Task<HttpResponseMessage> UploadImage(string url, byte[] ImageData)
{
    var requestContent = new MultipartFormDataContent(); 
    //    here you can specify boundary if you need---^
    var imageContent = new ByteArrayContent(ImageData);
    imageContent.Headers.ContentType = 
        MediaTypeHeaderValue.Parse("image/jpeg");

    requestContent.Add(imageContent, "image", "image.jpg");

    return await client.PostAsync(url, requestContent);
}

(Anda dapat requestContent.Add()apa pun yang Anda inginkan, lihat keturunan HttpContent untuk melihat tipe yang tersedia untuk dilewati)

Setelah selesai, Anda akan menemukan konten respons di dalamnya HttpResponseMessage.Contentyang dapat Anda konsumsi HttpContent.ReadAs*Async.

Ini adalah contoh cara memposting string dan aliran file dengan HTTPClient menggunakan MultipartFormDataContent. Disposisi Konten dan Tipe Konten perlu ditentukan untuk setiap konten HTTPC:

Inilah contoh saya. Semoga ini bisa membantu:

private static void Upload()
{
    using (var client = new HttpClient())
    {
        client.DefaultRequestHeaders.Add("User-Agent", "CBS Brightcove API Service");

        using (var content = new MultipartFormDataContent())
        {
            var path = @"C:\B2BAssetRoot\files\596086\596086.1.mp4";

            string assetName = Path.GetFileName(path);

            var request = new HTTPBrightCoveRequest()
                {
                    Method = "create_video",
                    Parameters = new Params()
                        {
                            CreateMultipleRenditions = "true",
                            EncodeTo = EncodeTo.Mp4.ToString().ToUpper(),
                            Token = "x8sLalfXacgn-4CzhTBm7uaCxVAPjvKqTf1oXpwLVYYoCkejZUsYtg..",
                            Video = new Video()
                                {
                                    Name = assetName,
                                    ReferenceId = Guid.NewGuid().ToString(),
                                    ShortDescription = assetName
                                }
                        }
                };

            //Content-Disposition: form-data; name="json"
            var stringContent = new StringContent(JsonConvert.SerializeObject(request));
            stringContent.Headers.Add("Content-Disposition", "form-data; name=\"json\"");
            content.Add(stringContent, "json");

            FileStream fs = File.OpenRead(path);

            var streamContent = new StreamContent(fs);
            streamContent.Headers.Add("Content-Type", "application/octet-stream");
            //Content-Disposition: form-data; name="file"; filename="C:\B2BAssetRoot\files\596090\596090.1.mp4";
            streamContent.Headers.Add("Content-Disposition", "form-data; name=\"file\"; filename=\"" + Path.GetFileName(path) + "\"");
            content.Add(streamContent, "file", Path.GetFileName(path));

            //content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment");

            Task<HttpResponseMessage> message = client.PostAsync("http://api.brightcove.com/services/post", content);

            var input = message.Result.Content.ReadAsStringAsync();
            Console.WriteLine(input.Result);
            Console.Read();
        }
    }
}

Berikut adalah contoh lain tentang cara menggunakan HttpClientuntuk mengunggah a multipart/form-data.

Ini mengunggah file ke REST API dan menyertakan file itu sendiri (misalnya JPG) dan parameter API tambahan. File langsung diunggah dari disk lokal melalui FileStream.

Lihat di sini untuk contoh lengkap termasuk tambahan logika spesifik API.

public static async Task UploadFileAsync(string token, string path, string channels)
{
    // we need to send a request with multipart/form-data
    var multiForm = new MultipartFormDataContent();

    // add API method parameters
    multiForm.Add(new StringContent(token), "token");
    multiForm.Add(new StringContent(channels), "channels");

    // add file and directly upload it
    FileStream fs = File.OpenRead(path);
    multiForm.Add(new StreamContent(fs), "file", Path.GetFileName(path));

    // send request to API
    var url = "https://slack.com/api/files.upload";
    var response = await client.PostAsync(url, multiForm);
}

Coba ini bekerja untuk saya.

private static async Task<object> Upload(string actionUrl)
{
    Image newImage = Image.FromFile(@"Absolute Path of image");
    ImageConverter _imageConverter = new ImageConverter();
    byte[] paramFileStream= (byte[])_imageConverter.ConvertTo(newImage, typeof(byte[]));

    var formContent = new MultipartFormDataContent
    {
        // Send form text values here
        {new StringContent("value1"),"key1"},
        {new StringContent("value2"),"key2" },
        // Send Image Here
        {new StreamContent(new MemoryStream(paramFileStream)),"imagekey","filename.jpg"}
    };

    var myHttpClient = new HttpClient();
    var response = await myHttpClient.PostAsync(actionUrl.ToString(), formContent);
    string stringContent = await response.Content.ReadAsStringAsync();

    return response;
}

Ini contoh lengkap yang bekerja untuk saya. The boundarynilai dalam permintaan ditambahkan secara otomatis oleh NET.

var url = "http://localhost/api/v1/yourendpointhere";
var filePath = @"C:\path\to\image.jpg";

HttpClient httpClient = new HttpClient();
MultipartFormDataContent form = new MultipartFormDataContent();

FileStream fs = File.OpenRead(filePath);
var streamContent = new StreamContent(fs);

var imageContent = new ByteArrayContent(streamContent.ReadAsByteArrayAsync().Result);
imageContent.Headers.ContentType = MediaTypeHeaderValue.Parse("multipart/form-data");

form.Add(imageContent, "image", Path.GetFileName(filePath));
var response = httpClient.PostAsync(url, form).Result;

Contoh dengan preloader Dotnet 3.0 Core

ProgressMessageHandler processMessageHander = new ProgressMessageHandler();

processMessageHander.HttpSendProgress += (s, e) =>
{
    if (e.ProgressPercentage > 0)
    {
        ProgressPercentage = e.ProgressPercentage;
        TotalBytes = e.TotalBytes;
        progressAction?.Invoke(progressFile);
    }
};

using (var client = HttpClientFactory.Create(processMessageHander))
{
    var uri = new Uri(transfer.BackEndUrl);
    client.DefaultRequestHeaders.Authorization =
    new AuthenticationHeaderValue("Bearer", AccessToken);

    using (MultipartFormDataContent multiForm = new MultipartFormDataContent())
    {
        multiForm.Add(new StringContent(FileId), "FileId");
        multiForm.Add(new StringContent(FileName), "FileName");
        string hash = "";

        using (MD5 md5Hash = MD5.Create())
        {
            var sb = new StringBuilder();
            foreach (var data in md5Hash.ComputeHash(File.ReadAllBytes(FullName)))
            {
                sb.Append(data.ToString("x2"));
            }
            hash = result.ToString();
        }
        multiForm.Add(new StringContent(hash), "Hash");

        using (FileStream fs = File.OpenRead(FullName))
        {
            multiForm.Add(new StreamContent(fs), "file", Path.GetFileName(FullName));
            var response = await client.PostAsync(uri, multiForm);
            progressFile.Message = response.ToString();

            if (response.IsSuccessStatusCode) {
                progressAction?.Invoke(progressFile);
            } else {
                progressErrorAction?.Invoke(progressFile);
            }
            response.EnsureSuccessStatusCode();
        }
    }
}

X509Certificate clientKey1 = null;
clientKey1 = new X509Certificate(AppSetting["certificatePath"],
AppSetting["pswd"]);
string url = "https://EndPointAddress";
FileStream fs = File.OpenRead(FilePath);
var streamContent = new StreamContent(fs);

var FileContent = new ByteArrayContent(streamContent.ReadAsByteArrayAsync().Result);
FileContent.Headers.ContentType = MediaTypeHeaderValue.Parse("ContentType");
var handler = new WebRequestHandler();


handler.ClientCertificateOptions = ClientCertificateOption.Manual;
handler.ClientCertificates.Add(clientKey1);
handler.ServerCertificateValidationCallback = (httpRequestMessage, cert, cetChain, policyErrors) =>
{
    return true;
};


using (var client = new HttpClient(handler))
{
    // Post it
    HttpResponseMessage httpResponseMessage = client.PostAsync(url, FileContent).Result;

    if (!httpResponseMessage.IsSuccessStatusCode)
    {
        string ss = httpResponseMessage.StatusCode.ToString();
    }
}

Saya menambahkan cuplikan kode yang menunjukkan cara memposting file ke API yang telah diekspos di DELETE http verb. Ini bukan kasus umum untuk mengunggah file dengan DELETE http verb tetapi diizinkan. Saya berasumsi otentikasi Windows NTLM untuk otorisasi panggilan.

Masalah yang mungkin dihadapi adalah bahwa semua kelebihan HttpClient.DeleteAsyncmetode tidak memiliki parameter untuk HttpContentcara kita mendapatkannya dalam PostAsyncmetode

var requestUri = new Uri("http://UrlOfTheApi");
using (var streamToPost = new MemoryStream("C:\temp.txt"))
using (var fileStreamContent = new StreamContent(streamToPost))
using (var httpClientHandler = new HttpClientHandler() { UseDefaultCredentials = true })
using (var httpClient = new HttpClient(httpClientHandler, true))
using (var requestMessage = new HttpRequestMessage(HttpMethod.Delete, requestUri))
using (var formDataContent = new MultipartFormDataContent())
{
    formDataContent.Add(fileStreamContent, "myFile", "temp.txt");
    requestMessage.Content = formDataContent;
    var response = httpClient.SendAsync(requestMessage).GetAwaiter().GetResult();

    if (response.IsSuccessStatusCode)
    {
        // File upload was successfull
    }
    else
    {
        var erroResult = response.Content.ReadAsStringAsync().GetAwaiter().GetResult();
        throw new Exception("Error on the server : " + erroResult);
    }
}

Anda perlu ruang nama di bawah ini di bagian atas file C # Anda:

using System;
using System.Net;
using System.IO;
using System.Net.Http;

PS Maaf tentang begitu banyak menggunakan blok (pola IDisposable) dalam kode saya. Sayangnya, sintaks menggunakan konstruk C # tidak mendukung inisialisasi beberapa variabel dalam satu pernyataan.

public async Task<object> PassImageWithText(IFormFile files)
{
    byte[] data;
    string result = "";
    ByteArrayContent bytes;

    MultipartFormDataContent multiForm = new MultipartFormDataContent();

    try
    {
        using (var client = new HttpClient())
        {
            using (var br = new BinaryReader(files.OpenReadStream()))
            {
                data = br.ReadBytes((int)files.OpenReadStream().Length);
            }

            bytes = new ByteArrayContent(data);
            multiForm.Add(bytes, "files", files.FileName);
            multiForm.Add(new StringContent("value1"), "key1");
            multiForm.Add(new StringContent("value2"), "key2");

            var res = await client.PostAsync(_MEDIA_ADD_IMG_URL, multiForm);
        }
    }
    catch (Exception e)
    {
        throw new Exception(e.ToString());
    }

    return result;
}