Dengan Swift 5, Anda dapat menggunakan salah satu dari lima cuplikan berikut untuk menyelesaikan masalah Anda.
# 1. Menggunakan Dictionary mapValues(_:)metode
let dictionary = ["foo": 1, "bar": 2, "baz": 5]
let newDictionary = dictionary.mapValues { value in
return value + 1
}
//let newDictionary = dictionary.mapValues { $0 + 1 } // also works
print(newDictionary) // prints: ["baz": 6, "foo": 2, "bar": 3]
# 2. Menggunakan Dictionary mapmetode dan init(uniqueKeysWithValues:)penginisialisasi
let dictionary = ["foo": 1, "bar": 2, "baz": 5]
let tupleArray = dictionary.map { (key: String, value: Int) in
return (key, value + 1)
}
//let tupleArray = dictionary.map { ($0, $1 + 1) } // also works
let newDictionary = Dictionary(uniqueKeysWithValues: tupleArray)
print(newDictionary) // prints: ["baz": 6, "foo": 2, "bar": 3]
# 3. Menggunakan Dictionary reduce(_:_:)metode atau reduce(into:_:)metode
let dictionary = ["foo": 1, "bar": 2, "baz": 5]
let newDictionary = dictionary.reduce([:]) { (partialResult: [String: Int], tuple: (key: String, value: Int)) in
var result = partialResult
result[tuple.key] = tuple.value + 1
return result
}
print(newDictionary) // prints: ["baz": 6, "foo": 2, "bar": 3]
let dictionary = ["foo": 1, "bar": 2, "baz": 5]
let newDictionary = dictionary.reduce(into: [:]) { (result: inout [String: Int], tuple: (key: String, value: Int)) in
result[tuple.key] = tuple.value + 1
}
print(newDictionary) // prints: ["baz": 6, "foo": 2, "bar": 3]
# 4 Menggunakan Dictionary subscript(_:default:)subskrip
let dictionary = ["foo": 1, "bar": 2, "baz": 5]
var newDictionary = [String: Int]()
for (key, value) in dictionary {
newDictionary[key, default: value] += 1
}
print(newDictionary) // prints: ["baz": 6, "foo": 2, "bar": 3]
# 5 Menggunakan Dictionary subscript(_:)subskrip
let dictionary = ["foo": 1, "bar": 2, "baz": 5]
var newDictionary = [String: Int]()
for (key, value) in dictionary {
newDictionary[key] = value + 1
}
print(newDictionary) // prints: ["baz": 6, "foo": 2, "bar": 3]