Jika Anda ingin menghapus semua instance 4 tanpa perlu tahu indeksnya:
LINQ: (.NET Framework 3.5)
int[] numbers = { 1, 3, 4, 9, 2 };
int numToRemove = 4;
numbers = numbers.Where(val => val != numToRemove).ToArray();
Non-LINQ: (.NET Framework 2.0)
static bool isNotFour(int n)
{
return n != 4;
}
int[] numbers = { 1, 3, 4, 9, 2 };
numbers = Array.FindAll(numbers, isNotFour).ToArray();
Jika Anda ingin menghapus hanya contoh pertama:
LINQ: (.NET Framework 3.5)
int[] numbers = { 1, 3, 4, 9, 2, 4 };
int numToRemove = 4;
int numIndex = Array.IndexOf(numbers, numToRemove);
numbers = numbers.Where((val, idx) => idx != numIndex).ToArray();
Non-LINQ: (.NET Framework 2.0)
int[] numbers = { 1, 3, 4, 9, 2, 4 };
int numToRemove = 4;
int numIdx = Array.IndexOf(numbers, numToRemove);
List<int> tmp = new List<int>(numbers);
tmp.RemoveAt(numIdx);
numbers = tmp.ToArray();
Sunting: Jika Anda belum menemukan jawabannya, seperti yang ditunjukkan Malfist, Anda harus menargetkan .NET Framework 3.5 agar contoh kode LINQ berfungsi. Jika Anda menargetkan 2.0, Anda perlu merujuk contoh-contoh Non-LINQ.