Bagaimana Anda membuat daftar kunci utama dari tabel SQL Server?

Pertanyaan sederhana, bagaimana Anda membuat daftar kunci utama tabel dengan T-SQL? Saya tahu cara mendapatkan indeks di atas meja, tetapi tidak ingat cara mendapatkan PK.

SELECT Col.Column_Name from 
    INFORMATION_SCHEMA.TABLE_CONSTRAINTS Tab, 
    INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE Col 
WHERE 
    Col.Constraint_Name = Tab.Constraint_Name
    AND Col.Table_Name = Tab.Table_Name
    AND Constraint_Type = 'PRIMARY KEY'
    AND Col.Table_Name = '<your table name>'

Biasanya praktik yang disarankan sekarang untuk menggunakan sys.*tampilan INFORMATION_SCHEMAdi SQL Server, jadi kecuali jika Anda berencana untuk memigrasi database, saya akan menggunakannya. Inilah cara Anda melakukannya dengan sys.*tampilan:

SELECT 
    c.name AS column_name,
    i.name AS index_name,
    c.is_identity
FROM sys.indexes i
    inner join sys.index_columns ic  ON i.object_id = ic.object_id AND i.index_id = ic.index_id
    inner join sys.columns c ON ic.object_id = c.object_id AND c.column_id = ic.column_id
WHERE i.is_primary_key = 1
    and i.object_ID = OBJECT_ID('<schema>.<tablename>');

Ini adalah solusi yang hanya menggunakan sys -tables.

Ini mencantumkan semua kunci utama dalam database. Ini mengembalikan skema, nama tabel, nama kolom dan urutan kolom yang benar untuk setiap kunci utama.

Jika Anda ingin mendapatkan kunci utama untuk tabel tertentu, Anda perlu memfilter SchemaNamedanTableName .

IMHO, solusi ini sangat umum dan tidak menggunakan literal string apa pun, sehingga dapat berjalan di mesin apa pun.

select 
    s.name as SchemaName,
    t.name as TableName,
    tc.name as ColumnName,
    ic.key_ordinal as KeyOrderNr
from 
    sys.schemas s 
    inner join sys.tables t   on s.schema_id=t.schema_id
    inner join sys.indexes i  on t.object_id=i.object_id
    inner join sys.index_columns ic on i.object_id=ic.object_id 
                                   and i.index_id=ic.index_id
    inner join sys.columns tc on ic.object_id=tc.object_id 
                             and ic.column_id=tc.column_id
where i.is_primary_key=1 
order by t.name, ic.key_ordinal ;

Berikut cara lain dari pertanyaan, dapatkan kunci utama tabel menggunakan kueri sql :

SELECT COLUMN_NAME
FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE
WHERE OBJECTPROPERTY(OBJECT_ID(CONSTRAINT_SCHEMA+'.'+CONSTRAINT_NAME), 'IsPrimaryKey') = 1
  AND TABLE_NAME = '<your table name>'

Ini digunakan KEY_COLUMN_USAGEuntuk menentukan batasan untuk tabel tertentu
Kemudian digunakan untuk menentukan apakah masing-masing adalah kunci primerOBJECTPROPERTY(id, 'IsPrimaryKey')

Saya suka teknik INFORMATION_SCHEMA, tetapi teknik lain yang pernah saya gunakan adalah: exec sp_pkeys 'table'

Apakah menggunakan MS SQL Server Anda dapat melakukan hal berikut:

--List all tables primary keys
select * from information_schema.table_constraints
where constraint_type = 'Primary Key'

Anda juga dapat memfilter pada kolom nama_tabel jika Anda menginginkan tabel tertentu.

--Ini adalah Versi Modifikasi lain yang juga merupakan contoh untuk Kueri Terkait Bersama

SELECT TC.TABLE_NAME as [Table_name], TC.CONSTRAINT_NAME as [Primary_Key]
 FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS TC
 INNER JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE CCU
 ON TC.CONSTRAINT_NAME = CCU.CONSTRAINT_NAME
 WHERE TC.CONSTRAINT_TYPE = 'PRIMARY KEY' AND
 TC.TABLE_NAME IN
 (SELECT [NAME] AS [TABLE_NAME] FROM SYS.OBJECTS 
 WHERE TYPE = 'U')

Ini harus mencantumkan semua batasan (Kunci utama dan Kunci Asing) dan di akhir kueri masukkan nama tabel

/* CAST IS DONE , SO THAT OUTPUT INTEXT FILE REMAINS WITH SCREEN LIMIT*/
WITH   ALL_KEYS_IN_TABLE (CONSTRAINT_NAME,CONSTRAINT_TYPE,PARENT_TABLE_NAME,PARENT_COL_NAME,PARENT_COL_NAME_DATA_TYPE,REFERENCE_TABLE_NAME,REFERENCE_COL_NAME) 
AS
(
SELECT  CONSTRAINT_NAME= CAST (PKnUKEY.name AS VARCHAR(30)) ,
        CONSTRAINT_TYPE=CAST (PKnUKEY.type_desc AS VARCHAR(30)) ,
        PARENT_TABLE_NAME=CAST (PKnUTable.name AS VARCHAR(30)) ,
        PARENT_COL_NAME=CAST ( PKnUKEYCol.name AS VARCHAR(30)) ,
        PARENT_COL_NAME_DATA_TYPE=  oParentColDtl.DATA_TYPE,        
        REFERENCE_TABLE_NAME='' ,
        REFERENCE_COL_NAME='' 

FROM sys.key_constraints as PKnUKEY
    INNER JOIN sys.tables as PKnUTable
            ON PKnUTable.object_id = PKnUKEY.parent_object_id
    INNER JOIN sys.index_columns as PKnUColIdx
            ON PKnUColIdx.object_id = PKnUTable.object_id
            AND PKnUColIdx.index_id = PKnUKEY.unique_index_id
    INNER JOIN sys.columns as PKnUKEYCol
            ON PKnUKEYCol.object_id = PKnUTable.object_id
            AND PKnUKEYCol.column_id = PKnUColIdx.column_id
     INNER JOIN INFORMATION_SCHEMA.COLUMNS oParentColDtl
            ON oParentColDtl.TABLE_NAME=PKnUTable.name
            AND oParentColDtl.COLUMN_NAME=PKnUKEYCol.name
UNION ALL
SELECT  CONSTRAINT_NAME= CAST (oConstraint.name AS VARCHAR(30)) ,
        CONSTRAINT_TYPE='FK',
        PARENT_TABLE_NAME=CAST (oParent.name AS VARCHAR(30)) ,
        PARENT_COL_NAME=CAST ( oParentCol.name AS VARCHAR(30)) ,
        PARENT_COL_NAME_DATA_TYPE= oParentColDtl.DATA_TYPE,     
        REFERENCE_TABLE_NAME=CAST ( oReference.name AS VARCHAR(30)) ,
        REFERENCE_COL_NAME=CAST (oReferenceCol.name AS VARCHAR(30)) 
FROM sys.foreign_key_columns FKC
    INNER JOIN sys.sysobjects oConstraint
            ON FKC.constraint_object_id=oConstraint.id 
    INNER JOIN sys.sysobjects oParent
            ON FKC.parent_object_id=oParent.id
    INNER JOIN sys.all_columns oParentCol
            ON FKC.parent_object_id=oParentCol.object_id /* ID of the object to which this column belongs.*/
            AND FKC.parent_column_id=oParentCol.column_id/* ID of the column. Is unique within the object.Column IDs might not be sequential.*/
    INNER JOIN sys.sysobjects oReference
            ON FKC.referenced_object_id=oReference.id
    INNER JOIN INFORMATION_SCHEMA.COLUMNS oParentColDtl
            ON oParentColDtl.TABLE_NAME=oParent.name
            AND oParentColDtl.COLUMN_NAME=oParentCol.name
    INNER JOIN sys.all_columns oReferenceCol
            ON FKC.referenced_object_id=oReferenceCol.object_id /* ID of the object to which this column belongs.*/
            AND FKC.referenced_column_id=oReferenceCol.column_id/* ID of the column. Is unique within the object.Column IDs might not be sequential.*/

)

select * from   ALL_KEYS_IN_TABLE
where   
    PARENT_TABLE_NAME  in ('YOUR_TABLE_NAME') 
    or REFERENCE_TABLE_NAME  in ('YOUR_TABLE_NAME')
ORDER BY PARENT_TABLE_NAME,CONSTRAINT_NAME;

Untuk referensi, silakan baca melalui - http://blogs.msdn.com/b/sqltips/archive/2005/09/16/469136.aspx

SELECT t.name AS 'table', i.name AS 'index', it.xtype,

(SELECT c.name FROM syscolumns c INNER JOIN sysindexkeys k 
    ON k.indid = i.indid 
        AND c.colid = k.colid 
        AND c.id = t.id 
        AND k.keyno = 1 
        AND k.id = t.id)
    AS 'column1',

(SELECT c.name FROM syscolumns c INNER JOIN sysindexkeys k 
    ON k.indid = i.indid 
        AND c.colid = k.colid 
        AND c.id = t.id 
        AND k.keyno = 2 
        AND k.id = t.id)
    AS 'column2',

(SELECT c.name FROM syscolumns c INNER JOIN sysindexkeys k 
    ON k.indid = i.indid 
        AND c.colid = k.colid 
        AND c.id = t.id 
        AND k.keyno = 3
        AND k.id = t.id)
    AS 'column3',

(SELECT c.name FROM syscolumns c INNER JOIN sysindexkeys k 
    ON k.indid = i.indid 
        AND c.colid = k.colid 
        AND c.id = t.id 
        AND k.keyno = 4
        AND k.id = t.id)
    AS 'column4',

(SELECT c.name FROM syscolumns c INNER JOIN sysindexkeys k 
    ON k.indid = i.indid 
        AND c.colid = k.colid 
        AND c.id = t.id 
        AND k.keyno = 5
        AND k.id = t.id)
    AS 'column5',

(SELECT c.name FROM syscolumns c INNER JOIN sysindexkeys k 
    ON k.indid = i.indid 
        AND c.colid = k.colid 
        AND c.id = t.id 
        AND k.keyno = 6
        AND k.id = t.id)
    AS 'column6',

(SELECT c.name FROM syscolumns c INNER JOIN sysindexkeys k 
    ON k.indid = i.indid 
        AND c.colid = k.colid 
        AND c.id = t.id 
        AND k.keyno = 7
        AND k.id = t.id)
    AS 'column7',

(SELECT c.name FROM syscolumns c INNER JOIN sysindexkeys k 
    ON k.indid = i.indid 
        AND c.colid = k.colid 
        AND c.id = t.id 
        AND k.keyno = 8 
        AND k.id = t.id)
    AS 'column8',

(SELECT c.name FROM syscolumns c INNER JOIN sysindexkeys k 
    ON k.indid = i.indid 
        AND c.colid = k.colid 
        AND c.id = t.id 
        AND k.keyno = 9 
        AND k.id = t.id)
    AS 'column9',

(SELECT c.name FROM syscolumns c INNER JOIN sysindexkeys k 
    ON k.indid = i.indid 
        AND c.colid = k.colid 
        AND c.id = t.id 
        AND k.keyno = 10
        AND k.id = t.id)
    AS 'column10',

FROM sysobjects t
    INNER JOIN sysindexes i ON i.id = t.id 
    INNER JOIN sysobjects it ON it.parent_obj = t.id AND it.name = i.name

WHERE it.xtype = 'PK'
ORDER BY t.name, i.name

Terimakasih teman.

Dengan sedikit variasi saya menggunakannya untuk menemukan semua kunci utama untuk semua tabel.

SELECT A.Name,Col.Column_Name from 
    INFORMATION_SCHEMA.TABLE_CONSTRAINTS Tab, 
    INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE Col ,
    (select NAME from dbo.sysobjects where xtype='u') AS A
WHERE 
    Col.Constraint_Name = Tab.Constraint_Name
    AND Col.Table_Name = Tab.Table_Name
    AND Constraint_Type = 'PRIMARY KEY '
    AND Col.Table_Name = A.Name

SELECT A.TABLE_NAME as [Table_name], A.CONSTRAINT_NAME as [Primary_Key]
 FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS A, INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE B
 WHERE CONSTRAINT_TYPE = 'PRIMARY KEY' AND A.CONSTRAINT_NAME = B.CONSTRAINT_NAME

Yang ini memberi Anda kolom yang PK.

SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE WHERE TABLE_NAME = 'TableName'

Prosedur tersimpan sistem sp_helpakan memberi Anda informasi. Jalankan pernyataan berikut:

execute sp_help table_name

Kueri di bawah ini akan mencantumkan kunci utama dari tabel tertentu :

SELECT DISTINCT
    CONSTRAINT_NAME AS [Constraint],
    TABLE_SCHEMA AS [Schema],
    TABLE_NAME AS TableName
FROM
    INFORMATION_SCHEMA.KEY_COLUMN_USAGE
WHERE
    TABLE_NAME = 'mytablename'

Saya menceritakan Teknik sederhana yang saya ikuti

SP_HELP 'table_name'

jalankan kode ini sebagai kueri. Sebutkan nama tabel Anda di tempat table_name yang ingin Anda ketahui Kunci Primernya (jangan lupa tanda kutip tunggal). Hasilnya akan terlihat seperti Gambar terlampir. Semoga bisa membantu Anda

Untuk daftar kolom kunci utama yang dipisahkan koma untuk NamaTabel dan Skema:

Select distinct SUBSTRING ( stuff(( select distinct ',' + [COLUMN_NAME] 
                                    from INFORMATION_SCHEMA.KEY_COLUMN_USAGE  
                                    where OBJECTPROPERTY(OBJECT_ID(CONSTRAINT_SCHEMA + '.' + QUOTENAME(CONSTRAINT_NAME)), 'IsPrimaryKey') = 1  
                                    AND TABLE_NAME = 'TableName' AND TABLE_SCHEMA = 'Schema'  
                                    order by 1 FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'),1,0,'' ) 
                            ,2,9999) 

Cobalah ini:

SELECT
    CONSTRAINT_CATALOG AS DataBaseName,
    CONSTRAINT_SCHEMA AS SchemaName,
    TABLE_NAME AS TableName,
    CONSTRAINT_Name AS PrimaryKey
FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS 
WHERE CONSTRAINT_TYPE = 'Primary Key' and Table_Name = 'YourTable'

Versi ini menampilkan skema, nama tabel, dan daftar kunci primer yang diurutkan dengan dipisahkan koma. Object_Id () tidak berfungsi untuk server tautan jadi kami memfilter berdasarkan nama tabel.

Tanpa REPLACE (Si1.Column_Name, '', '') itu akan menampilkan tag pembuka dan penutup xml untuk Column_Name pada database yang saya uji. Saya tidak yakin mengapa database memerlukan penggantian untuk 'Column_Name' jadi jika ada yang tahu silahkan berkomentar.

DECLARE @TableName VARCHAR(100) = '';
WITH Sysinfo
    AS (SELECT Kcu.Table_Name
            , Kcu.Table_Schema AS Schema_Name
            , Kcu.Column_Name
            , Kcu.Ordinal_Position
        FROM   [LinkServer].Information_Schema.Key_Column_Usage Kcu
             JOIN [LinkServer].Information_Schema.Table_Constraints AS Tc ON Tc.Constraint_Name = Kcu.Constraint_Name
        WHERE  Tc.Constraint_Type = 'Primary Key')
    SELECT           Schema_Name
                    ,Table_Name
                    , STUFF(
                          (
                             SELECT ', '
                                 , REPLACE(Si1.Column_Name, '', '')
                             FROM    Sysinfo Si1
                             WHERE  Si1.Table_Name = Si2.Table_Name
                             ORDER BY Si1.Table_Name
                                   , Si1.Ordinal_Position
                             FOR XML PATH('')
                          ), 1, 2, '') AS Primary_Keys
    FROM Sysinfo Si2
    WHERE Table_Name = CASE
                       WHEN @TableName NOT IN( '', 'All')
                       THEN @TableName
                       ELSE Table_Name
                    END
    GROUP BY Si2.Table_Name, Si2.Schema_Name;

Dan pola yang sama menggunakan kueri George:

DECLARE @TableName VARCHAR(100) = '';
WITH Sysinfo
    AS (SELECT S.Name AS Schema_Name
            , T.Name AS Table_Name
            , Tc.Name AS Column_Name
            , Ic.Key_Ordinal AS Ordinal_Position
        FROM   [LinkServer].Sys.Schemas S
             JOIN [LinkServer].Sys.Tables T ON S.Schema_Id = T.Schema_Id
             JOIN [LinkServer].Sys.Indexes I ON T.Object_Id = I.Object_Id
             JOIN [LinkServer].Sys.Index_Columns Ic ON I.Object_Id = Ic.Object_Id
                                                       AND I.Index_Id = Ic.Index_Id
             JOIN [LinkServer].Sys.Columns Tc ON Ic.Object_Id = Tc.Object_Id
                                                  AND Ic.Column_Id = Tc.Column_Id
        WHERE  I.Is_Primary_Key = 1)
    SELECT           Schema_Name
                    ,Table_Name
                    , STUFF(
                          (
                             SELECT ', '
                                 , REPLACE(Si1.Column_Name, '', '')
                             FROM    Sysinfo Si1
                             WHERE  Si1.Table_Name = Si2.Table_Name
                             ORDER BY Si1.Table_Name
                                   , Si1.Ordinal_Position
                             FOR XML PATH('')
                          ), 1, 2, '') AS Primary_Keys
    FROM Sysinfo Si2
    WHERE Table_Name = CASE
                       WHEN @TableName NOT IN('', 'All')
                       THEN @TableName
                       ELSE Table_Name
                    END
    GROUP BY Si2.Table_Name, Si2.Schema_Name;

Saya menemukan ini berguna, memberikan daftar tabel dengan daftar kolom yang terpisah koma dan kemudian juga daftar terpisah koma yang merupakan kunci utama

SELECT T.TABLE_SCHEMA, T.TABLE_NAME, 
STUFF((
    SELECT ', ' + C.COLUMN_NAME
    FROM INFORMATION_SCHEMA.COLUMNS C
        WHERE C.TABLE_SCHEMA = T.TABLE_SCHEMA
        AND T.TABLE_NAME = C.TABLE_NAME
        FOR XML PATH ('')
    ), 1, 2, '') AS Columns,
STUFF((
SELECT ', ' + C.COLUMN_NAME 
FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE C
INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS TC
    ON C.TABLE_SCHEMA = TC.TABLE_SCHEMA
    AND C.TABLE_NAME = TC.TABLE_NAME
    WHERE C.TABLE_SCHEMA = T.TABLE_SCHEMA
    AND T.TABLE_NAME = C.TABLE_NAME
    AND TC.CONSTRAINT_TYPE = 'PRIMARY KEY'
    FOR XML PATH ('')
), 1, 2, '') AS [Key]
FROM INFORMATION_SCHEMA.TABLES T
ORDER BY T.TABLE_SCHEMA, T.TABLE_NAME

Tabel Sys.Objects berisi baris untuk setiap objek dengan cakupan skema yang ditentukan pengguna.

Batasan yang dibuat seperti Kunci Utama atau lainnya akan menjadi objek dan nama Tabel akan menjadi objek_tuanya

Query sys.Objects dan kumpulkan Id Objek dari Jenis yang Diperlukan

declare @TableName nvarchar(50)='TblInvoice' -- your table name
declare @TypeOfKey nvarchar(50)='PK' -- For Primary key

SELECT Name FROM sys.objects
WHERE type = @TypeOfKey 
AND  parent_object_id = OBJECT_ID (@TableName)

Izinkan saya menyarankan jawaban sederhana yang lebih akurat untuk pertanyaan asli di bawah ini

SELECT 
KEYS.table_schema, KEYS.table_name, KEYS.column_name, KEYS.ORDINAL_POSITION 
FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE keys
INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS CONS 
    ON cons.TABLE_SCHEMA = keys.TABLE_SCHEMA 
    AND cons.TABLE_NAME = keys.TABLE_NAME 
    AND cons.CONSTRAINT_NAME = keys.CONSTRAINT_NAME
WHERE cons.CONSTRAINT_TYPE = 'PRIMARY KEY'

Catatan:

1. Beberapa jawaban di atas tidak memiliki filter untuk kolom kunci utama saja!
2. Saya menggunakan di bawah ini dalam CTE untuk bergabung dengan daftar kolom yang lebih besar untuk memberikan metadata dari sumber untuk memberi makan pembuatan tabel pementasan BIML dan kode SSIS

Mungkin baru-baru ini diposting tetapi semoga ini akan membantu seseorang untuk melihat daftar kunci utama di server sql dengan menggunakan kueri t-sql ini:

SELECT  schema_name(t.schema_id) AS [schema_name], t.name AS TableName,        
    COL_NAME(ic.OBJECT_ID,ic.column_id) AS PrimaryKeyColumnName,
    i.name AS PrimaryKeyConstraintName
FROM    sys.tables t 
INNER JOIN sys.indexes AS i  on t.object_id=i.object_id 
INNER JOIN  sys.index_columns AS ic ON  i.OBJECT_ID = ic.OBJECT_ID
                            AND i.index_id = ic.index_id 
WHERE OBJECT_NAME(ic.OBJECT_ID) = 'YourTableNameHere'

Anda dapat melihat daftar semua kunci asing dengan menggunakan kueri ini jika Anda mungkin ingin:

SELECT
f.name as ForeignKeyConstraintName
,OBJECT_NAME(f.parent_object_id) AS ReferencingTableName
,COL_NAME(fc.parent_object_id, fc.parent_column_id) AS ReferencingColumnName
,OBJECT_NAME (f.referenced_object_id) AS ReferencedTableName
,COL_NAME(fc.referenced_object_id, fc.referenced_column_id) AS 
 ReferencedColumnName  ,delete_referential_action_desc AS 
DeleteReferentialActionDesc ,update_referential_action_desc AS 
UpdateReferentialActionDesc
FROM sys.foreign_keys AS f
INNER JOIN sys.foreign_key_columns AS fc
ON f.object_id = fc.constraint_object_id
 --WHERE OBJECT_NAME(f.parent_object_id) = 'YourTableNameHere' 
 --If you want to know referecing table details 
 WHERE OBJECT_NAME(f.referenced_object_id) = 'YourTableNameHere' 
 --If you want to know refereced table details 
ORDER BY f.name

Saya menemukan ini dari teman saya, sangat efektif jika Anda mencari semua kunci utama tabel di bawah skema tertentu.

SELECT tc.constraint_name AS IndexName,tc.table_name AS TableName,tc.table_schema
AS SchemaName,kc.column_name AS COLUMN_NAME
FROM information_schema.table_constraints tc,information_schema.key_column_usage kc
WHERE tc.constraint_type = 'PRIMARY KEY' AND kc.table_name = tc.table_name AND kc.table_schema = tc.table_schema
AND kc.constraint_name = tc.constraint_name AND tc.table_schema='<SCHEMA_NAME>'

Jika Anda ingin melakukan ORM Anda sendiri atau menghasilkan kode dari tabel tertentu, maka ini mungkin yang Anda cari:

declare @table varchar(100) = 'mytable';

with cte as
(
    select 
        tc.CONSTRAINT_SCHEMA
        , tc.CONSTRAINT_TYPE
        , tc.TABLE_NAME
        , ccu.COLUMN_NAME
        , IS_NULLABLE
        , DATA_TYPE
        , CHARACTER_MAXIMUM_LENGTH
        , NUMERIC_PRECISION
    from 
        INFORMATION_SCHEMA.TABLE_CONSTRAINTS tc 
        inner join INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE ccu on tc.TABLE_NAME=ccu.TABLE_NAME  and tc.TABLE_SCHEMA=ccu.TABLE_SCHEMA
        inner join information_schema.COLUMNS c on ccu.COLUMN_NAME=c.COLUMN_NAME and ccu.TABLE_NAME=c.TABLE_NAME and ccu.TABLE_SCHEMA=c.TABLE_SCHEMA
    where 
        tc.table_name=@table
        and 
        ccu.CONSTRAINT_NAME=tc.CONSTRAINT_NAME
    union 
    select TABLE_SCHEMA,'COLUMN', TABLE_NAME, COLUMN_NAME, IS_NULLABLE, DATA_TYPE,CHARACTER_MAXIMUM_LENGTH, NUMERIC_PRECISION from INFORMATION_SCHEMA.COLUMNS where TABLE_NAME=@table
    and COLUMN_NAME not in (select COLUMN_NAME from INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE where TABLE_NAME = @table)
)
select 
    cast(iif(CONSTRAINT_TYPE='PRIMARY KEY',1,0) as bit) PrimaryKey
    ,cast(iif(CONSTRAINT_TYPE='FOREIGN KEY',1,0) as bit) ForeignKey
    ,cast(iif(CONSTRAINT_TYPE='COLUMN',1,0) as bit) NotKey
    ,COLUMN_NAME
    ,cast(iif(is_nullable='NO',0,1) as bit) IsNullable
    , DATA_TYPE
    , CHARACTER_MAXIMUM_LENGTH
    , NUMERIC_PRECISION 
from 
    cte 
order by 
    case CONSTRAINT_TYPE 
        when 'PRIMARY KEY' then 1 
        when 'FOREIGN KEY' then 2 
        else 3 end
    , COLUMN_NAME

Hasilnya akan terlihat seperti ini:

				<table cellspacing=0 border=1>
					<tr>
						<td style=min-width:50px>PrimaryKey</td>
						<td style=min-width:50px>ForeignKey</td>
						<td style=min-width:50px>NotKey</td>
						<td style=min-width:50px>COLUMN_NAME</td>
						<td style=min-width:50px>IsNullable</td>
						<td style=min-width:50px>DATA_TYPE</td>
						<td style=min-width:50px>CHARACTER_MAXIMUM_LENGTH</td>
						<td style=min-width:50px>NUMERIC_PRECISION</td>
					</tr>
					<tr>
						<td style=min-width:50px>1</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>LectureNoteID</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>int</td>
						<td style=min-width:50px>NULL</td>
						<td style=min-width:50px>10</td>
					</tr>
					<tr>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>1</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>LectureId</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>int</td>
						<td style=min-width:50px>NULL</td>
						<td style=min-width:50px>10</td>
					</tr>
					<tr>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>1</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>NoteTypeID</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>int</td>
						<td style=min-width:50px>NULL</td>
						<td style=min-width:50px>10</td>
					</tr>
					<tr>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>1</td>
						<td style=min-width:50px>Body</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>nvarchar</td>
						<td style=min-width:50px>-1</td>
						<td style=min-width:50px>NULL</td>
					</tr>
					<tr>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>1</td>
						<td style=min-width:50px>DisplayOrder</td>
						<td style=min-width:50px>0</td>
						<td style=min-width:50px>int</td>
						<td style=min-width:50px>NULL</td>
						<td style=min-width:50px>10</td>
					</tr>
				</table>
				

Jika Kunci Utama dan jenisnya diperlukan, kueri ini mungkin berguna:

SELECT L.TABLE_SCHEMA, L.TABLE_NAME, L.COLUMN_NAME, R.TypeName
FROM(
    SELECT COLUMN_NAME, TABLE_NAME, TABLE_SCHEMA
    FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE
    WHERE OBJECTPROPERTY(OBJECT_ID(CONSTRAINT_SCHEMA + '.' + QUOTENAME(CONSTRAINT_NAME)), 'IsPrimaryKey') = 1
)L
LEFT JOIN (
    SELECT
    OBJECT_NAME(c.OBJECT_ID) TableName ,c.name AS ColumnName ,t.name AS TypeName
    FROM sys.columns AS c
    JOIN sys.types AS t ON c.user_type_id=t.user_type_id
)R ON L.COLUMN_NAME = R.ColumnName AND L.TABLE_NAME = R.TableName