Adakah yang bisa memberi tahu saya mengapa ini terjadi? Saya bisa menyelesaikan nama host menggunakan host dan / atau nslookup tetapi pencarian maju tidak bekerja dengan menggali; reverse lookup lakukan:
musashixxx@box:~$ host someserver
someserver.somenet.internal has address 192.168.0.252
musashixxx@box:~$ host 192.168.0.252
252.0.168.192.in-addr.arpa domain name pointer someserver.somenet.internal.
musashixxx@box:~$ nslookup someserver
Server: 192.168.0.253
Address: 192.168.0.253#53
Name: someserver.somenet.internal
Address: 192.168.0.252
musashixxx@box:~$ nslookup 192.168.0.252
Server: 192.168.0.253
Address: 192.168.0.253#53
252.0.168.192.in-addr.arpa name = someserver.somenet.internal.
musashixxx@box:~$ dig someserver
; <<>> DiG 9.8.1-P1 <<>> someserver
;; global options: +cmd
;; Got answer:
;; ->>HEADER<<- opcode: QUERY, status: SERVFAIL, id: 55306
;; flags: qr rd ra; QUERY: 1, ANSWER: 0, AUTHORITY: 0, ADDITIONAL: 0
;; QUESTION SECTION:
;someserver. IN A
;; Query time: 0 msec
;; SERVER: 192.168.0.253#53(192.168.0.253)
;; WHEN: Wed Oct 3 15:47:38 2012
;; MSG SIZE rcvd: 27
musashixxx@box:~$ dig -x 192.168.0.252
; <<>> DiG 9.8.1-P1 <<>> -x 192.168.0.252
;; global options: +cmd
;; Got answer:
;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 28126
;; flags: qr aa rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 0, ADDITIONAL: 0
;; QUESTION SECTION:
;252.0.168.192.in-addr.arpa. IN PTR
;; ANSWER SECTION:
252.0.168.192.in-addr.arpa. 3600 IN PTR someserver.somenet.internal.
;; Query time: 0 msec
;; SERVER: 192.168.0.253#53(192.168.0.253)
;; WHEN: Wed Oct 3 15:49:11 2012
;; MSG SIZE rcvd: 86
Begini tampilannya resolv.conf saya:
nameserver 192.168.0.253
search somenet.internal
Apakah perilaku ini normal? Adakah pikiran?